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barxatty [35]
2 years ago
12

What is 1/7 divided by 252 ?

Mathematics
1 answer:
miskamm [114]2 years ago
5 0

Answer:

In decimal form: 0.00056689342 (If wanted to round to nearest thousandth, 0.001)

In fraction form: \frac{1}{1764} or \frac{28344671}{50000000000}

Step-by-step explanation:

\frac{1}{7}\div \:252=\frac{1}{1764}

\mathrm{Convert\:element\:to\:fraction}:\quad \:252=\frac{252}{1}\\=\frac{1}{7}\div \frac{252}{1}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}\\=\frac{1}{7}\times \frac{1}{252}

\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}\\=\frac{1\times \:1}{7\times \:252}

\mathrm{Multiply\:the\:numbers:}\:1\times \:1=1\\=\frac{1}{7\times \:252}

\mathrm{Multiply\:the\:numbers:}\:7\times \:252=1764\\=\frac{1}{1764}

Hopes this helps you!

Have a wonderful night!

Happy Monday!

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"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that give
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Answer:

a. answer to a can be found in the attached file

b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=

0.24+0.06+0.05 = 0.35

c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its  overall probability of survival?

Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07

Step-by-step explanation:

"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that gives a 0.8 chance of seed survival, a medium-quality soil that gives a 0.3 chance of survival, and a low-quality soil that gives only a 0.1 chance of survival. These three soil types (high, medium, and low) are present in the habitat in proportions of 30:20:50, respectively. The probability that a seed lands on a particular soil type is proportional to the frequency of that type in the habitat. a. Draw a probability tree to determine the probabilities of survival under all possible circumstances. b. What is the probability of survival of the seed, assuming that it lands"c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?

a. Find the probability tree as attached below

b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=

0.24+0.06+0.05 = 0.35

c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its  overall probability of survival?

Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07

Download docx
7 0
3 years ago
A line segment has<br> ____points.<br> Two<br> Zero<br> one<br> three
krok68 [10]

Answer:

zero

Step-by-step explanation:

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I barely ask questions but I really need help with #3 and a little with 4. On number four I got 1 1/20 which doesn’t seem right.
uranmaximum [27]
Let r, g and b represent red, green and blue.

r+g+b = 74

r=g-1

b=r+g

Again, r+g+b = 74.  Let's substitutte r+g for b:  r+g+(r+g) = 74.

Next, let's eliminate r.  Use r=g-1.  Then      g-1  + g + g-1 + g = 74

Combining the g terms,  4g - 2 = 74     => 4g = 76   =>  g = 19

Recall that r=g-1
and 
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Find r.  If r=g-1, and g=19, then r = 19-1=18

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So there are 37 blue candies, 18 red candies and 19 green candies.

Check:  37+18+19=74 ???  Yes.
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3 years ago
Read 2 more answers
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Answer:

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Step-by-step explanation:

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B) We can see that the first number is larger than the second number, so without doing too much math we can see this is our answer!

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C) 4:6

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D) 2:3

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2 years ago
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