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3 years ago

You walk 1/3 miles to a grocery store. Then you walk another 1/2 miles to a music store. How many miles have you walked in all?

Mathematics

2 answers:

Ksju [112]3 years ago

7 0

Answer:

5/6 miles

Step-by-step explanation:

When adding fractions with different denominators, we have to first find the LCM of the two denominators, and then multiply the fraction so that the denominator is the LCM.

The LCM of 2 and 3 is 6.

Thus, our two fractions become 2/6 and 3/6. Adding them gives us 5/6.

andriy [413]3 years ago

3 0

You have walked 5/6 miles

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Describe triangle ABC in terms of its sides and angles

Nimfa-mama [501]

Answer:

Right angle triangle

Step-by-step explanation:

Given triangle is right angle triangle
It is a type of triangle that has one of it's angles equal to 90 degrees.
The other two angle sum up to 90 degrees.
Here AC side is perpendicular and the AB side is base of the triangle.
And the third side that is called CB which longest side of all three sides that is called hypotenuse.

6 0

3 years ago

Read 2 more answers

Which statement is correct?

Arisa [49]

Answer:

$2.06 \times 10^-^2 = 206$

$1.88 \times 10^-^1 = 18.8$

$206 \times 18.8 = 3,872.8$

$7.69 \times 10^-^2 = 769$

$2.3 \times 10^-^5 = 230,000$

$=\frac{769}{230000}$

= 0.00334

therefore,

3,872.80 > 0.00334

Step-by-step explanation:

Which statement is correct?

(2.06x102x1.88 x 10-1) <7.69x 10

2.3x10-5

(2.06 x 10-2)(1.88 x 10-1) 7.69x 10-

2.3x10-5

7.69 x 10"

(2.06 x 10-2x1.88x10-)>

2.3x10-5

(2.06x 10-2X(1.88x 10-1)-7.69x104

2.3x10-5

Given that;

$2.06 \times 10^-^2 = 206$

$1.88 \times 10^-^1 = 18.8$

$206 \times 18.8 = 3,872.8$

$7.69 \times 10^-^2 = 769$

$2.3 \times 10^-^5 = 230,000$

$=\frac{769}{230000}$

= 0.00334

therefore,

3,872.80 > 0.00334

7 0

3 years ago

Please help ASAP work and answer please please

tiny-mole [99]

Answers:

8. 12x+3= 27

move 3 to the other side , sign changes from +3 to -3

12x+3-3=27-3

12x= 24

divide by 12 for both sides

12x/12=24/12

x= 2

9. 6(y-10)=42

mutiply the bracket by 6

(6)(y)(6)(-10)= 6y-60

6y-60= 42

move -60 to the other side, sign changes from -60 to +60

6y-60+60=42+60

6y=102

divide by 6

6y/6=102/6

y=17

10. 9x-2=4x+13

move +4x to the other side

9x-4x-2= 4x-4x+13

5x-2= 13

5x-2+2= 13+2

5x= 15

divide by 5 for both sides

5x/5= 15/5

x= 3

11. 4/3y+5/2y= 1

find the common denominator for both of the fractions which is 6.

Mutiply by 2 for 4/3y .

4(2)/3(2)y=8/6y

Mutiply by 3 for 5/2y

5(3)/2(3y)= 15/6y

8/6y+15/6y= 23/6y

23/6y= 1

Mutiply both sides by 6/23

23/6y(6/23)= 1 (6/23)

Cross out 6 and 6 , divide by 6 and then becomes 1.

Cross out 23 and 23, divide by 23 and then becomes 1.

1*1*y=y

y= 6/23

5 0

3 years ago

The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that

salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0

3 years ago

a boat builer wamts to make a modle of a schooner, a type of sailboatwith at least two masts. the schooner is 34 meters in lengt

BlackZzzverrR [31]

First you should set up fractions equal to each other to see the size ratio

8/34 = x/1.2

As to make comparable fractions. Then you would cross multiply in order to get
$34x = 9.6$
Divide both sides by 34 and you should get an answer of 0.28m for the model beam.

6 0

3 years ago