Answer:
let angle e be x
x+4x+10=180°[by linear pair]
5x+10=180°
5x=180-10
5x=170
x=170/5
x=34
angle E=34°
angle E+angle C+angle D=180°[by angle sum property]
34°+70°+2x=180°
104°+2x=180°
2x=180°-104
2x=76°
angle d=76°
I think it’s 35w because you distribute: 24w+11w ) and then you add.
Answer:
idk
Step-by-step explanation:
i have no clue
Answer
C) 160 in^2
Step by step explanation
First, let's find the area of the rectangle.
Area of a rectangle = length x width
The area of the rectangle = 20 * 10
= 200 in^2
Now let's find the area of the triangle that is removed.
Area of a triangle = 1/2 base * height.
Here base = 10 and height = 8. Plug in these values into the formula, we get
Area of the triangle = 1/2 * 10*8
= 5* 8
The area of the triangle = 40 in^2
The area of the remaining figure = Area of the rectangle - area of the triangle
= 200 - 40
= 160 in^2
The answer is "160 in^2"
Thank you.
Answer:
Wow I got the first step
are you looking for the
intersection of the line perpendicular
to plane 1 thorough the origin and plane 2
for the first part???
