The necessary solution that would be used to fill in the blanks would be
- perpendicular
- is the center of
- Circumscribed
<h3>How to find the center of the circle</h3>
The way that Quintin would be able to do this would be the center of the circumferential triangle is equidistant from the vertices.
The center is going to be the intersection of the bisectors of the three sides of the given triangle.
Read more on the center of a circle here:
brainly.com/question/25938130
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perpendicular bisectors, is the center of, circumscribed
8 would be the coefficient :)
Answer:
Step-by-step explanation:
Hello,
let's find a and b reals so that
we identify the terms in 
9 = 3a
we identify the terms in x
-18 = 3b + a
we identify the constant terms
-7 = b
so ti goes with a = 9/3 = 3, b = -7
so we can write
so 
hope this helps
I don’t think I just want points
Answer:
-499,485.
Step-by-step explanation:
We can transform this to an arithmetic series by working it out in pairs:
6^2 - 7^2 = (6-7)(6+7) = -13
8^2 - 9^2 = (8-9)*8+9) = -17
10^2 - 11^2 = -1 * 21 = -21 and so on
The common difference is -4.
The number of terms in this series is (998 - 6) / 2 + 1
= 992/2 + 1 = 497.
Sum of n terms of an A.S:
= n/2 [2a1 + (n - 1)d
Here a1 = -13, n = 497, d = -4:
Sum = (497/2)[-26 - 4(497-1)]
= 497/2 * -2010
= -499,485.
