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3 years ago

Someone help I’m stuck on this

Mathematics

1 answer:

aliina [53]3 years ago

3 0

Answer: 1 is 2 rectangles, 4 in a triangle and a rhombus I think.

Step-by-step explanation:

It says what would the shapes be shown as if it was split on the line.

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If s=13, find s-9. ________

Lady bird [3.3K]

Answer:s-9=3

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3 years ago

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Find the measure of the given angle.

Aleks04 [339]

Answer:

132

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3 years ago

The graph of g(x) is a reflection and translation of f(x) = 2x<br> Which equation represents g(x)?

lions [1.4K]

Answer:

-2x -1 if f(x) is reflected along the x axis and translated 1 unit downward

Step-by-step explanation:

A function can either be reflected along the x axis or along the y axis. If a function is reflected along the x axis, the new reflected equation g(x) is given by:

g(x) = -f(x) = -2x

g(x) = -2x

If a function is reflected along the y axis, the new reflected equation g(x) is given by:

g(x) = f(-x) = 2(-x)

g(x) = -2x

Translation means the shifting of the curve either up or down in a graph. If the reflected function is shifted 1 unit upward, the function becomes:

g(x) + 1 = -2x + 1

If the reflected function is shifted 1 unit downward, the function becomes:

g(x) - 1 = -2x - 1

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3 years ago

Solve the inequality -6x+28>=10

Nataly [62]

Answer:

x < 3

Step-by-step explanation:

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3 years ago

The probability that a car has a certain factory defect is 825. The probability that a car has a certain factory defect and need

ipn [44]

Answer:

90.91% probability that a car needs an oil change given that it has a certain factory defect

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this problem, we have that:

Event A: having a factory defect.

Event B: needing an oil change.

The probability that a car has a certain factory defect is 825.

So $P(A) = 0.825$

The probability that a car has a certain factory defect and needs an oil change is 750.

So $P(A \cap B) = 0.75$

What is the probability that a car needs an oil change given that it has a certain factory defect

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.75}{0.825} = 0.9091$

90.91% probability that a car needs an oil change given that it has a certain factory defect

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4 years ago