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Nutka1998 [239]
3 years ago
12

Choose the letter or letters of each correct answer.

Mathematics
1 answer:
SashulF [63]3 years ago
5 0

Answer:

b

Step-by-step explanation:

because b is more than a half.

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How many meters in three kilometer?
zhannawk [14.2K]
There are 3000 meters in 3 kilometer. meaning that 1 kilometer is equal to 1000 meters

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3 years ago
Find f(-6) for f(x) = x² - 4x + 5. Be sure to show<br> your work.
Marina86 [1]

substitute -6 in the equation:

f(x)=x^{2} -4x+5,\\f(-6)=(-6)^{2} -4(-6)+5\\f(-6)=36+24+5\\f(-6)=\boxed{65}

4 0
3 years ago
What’s the unit rate for 180 miles per 4 1/2 gallons
sasho [114]

Answer:

180 divided by 4.5 is 40 so the unit rate is 40 miles per gallon/ 40 over 1/ 40/1

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Below is the frequency distribution of the weights (in kg) of some sample of teen-agers.
julia-pushkina [17]

Usually, the terms “data” and “information” are used interchangeably. However, there is a subtle difference between the two.

In a nutshell, data can be a number, symbol, character, word, codes, graphs, etc. On the other hand, information is data put into context. Information is utilised by humans in some significant way (such as to make decisions, forecasts etc).

A basic example of information would be a computer. A computer uses programming scripts, formulas, or software applications to turn data into information.

Let us have a detailed look at the difference between data and information in a tabular column below

3 0
3 years ago
A manufacturer of radial tires for automobiles has extensive data to support the fact that the lifetime of their tires follows a
Diano4ka-milaya [45]

Answer:  (C) 0.1591

Step-by-step explanation:

Given : A manufacturer of radial tires for automobiles has extensive data to support the fact that the lifetime of their tires follows a normal distribution with

\mu=42,100\text{ miles}

\sigma=2,510\text{ miles}

Let x be the random variable that represents the lifetime of the tires .

z-score : z=\dfrac{x-\mu}{\sigma}

For x= 44,500 miles

z=\dfrac{44500-42100}{2510}\approx0.96

For x= 48,000 miles

z=\dfrac{48000-42100}{2510}\approx2.35

Using the standard normal distribution table , we have

The p-value : P(44500

P(z

Hence, the probability that a randomly selected tire will have a lifetime of between 44,500 miles and 48,000 miles =  0.1591

3 0
3 years ago
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