Answer:
To prove that 3·4ⁿ + 51 is divisible by 3 and 9, we have;
3·4ⁿ is divisible by 3 and 51 is divisible by 3
Where we have;
= 3·4ⁿ + 51
= 3·4ⁿ⁺¹ + 51
- = 3·4ⁿ⁺¹ + 51 - (3·4ⁿ + 51) = 3·4ⁿ⁺¹ - 3·4ⁿ
- = 3( 4ⁿ⁺¹ - 4ⁿ) = 3×4ⁿ×(4 - 1) = 9×4ⁿ
∴ - is divisible by 9
Given that we have for S₀ = 3×4⁰ + 51 = 63 = 9×7
∴ S₀ is divisible by 9
Since - is divisible by 9, we have;
- 
= 
- is divisible by 9
Therefore is divisible by 9 and is divisible by 9 for all positive integers n
Step-by-step explanation:
Answer:
-1
Step-by-step explanation:
Distribute
6x - 2 >= 4x - 6
2x >= -4
x >= -2
Both the numerator and denominator are divisible by 4, meaning that when they are both divided by this number they wll be in their simplest form.
e.g. 8/4=2 and 20/4=5
Therefore the simplest form is 2/5
Derslerinde başarılar dilerim
Answer:
16m and 12m
Step-by-step explanation:
2x + 2(x - 4) = 56
4x = 64
x = 16
Sides are 16 m and 12 m
