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Delvig [45]
3 years ago
11

I need some help ? Does anyone know this:)I’m new too this thats why im asking loll

Mathematics
1 answer:
zhuklara [117]3 years ago
3 0

Answer:

C≈31.42

Step-by-step explanation:

Radius=5 (10 divided by 2)

C=2πr

Brainly plss

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Anybody knows the answer?
soldi70 [24.7K]

Hey!


RS = 15 and RT = 18. Subtract 18 from 15 to get your answer.


18 - 15 = 3


<em>That means your answer is 3</em>


\framebox{Answer = 3}

8 0
3 years ago
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melissa is driving along a highway at a constant soeed of 65 mph. how long does it take her to travel 90 miles?
Umnica [9.8K]

Answer:

1.4 hours or 83 minutes

Step-by-step explanation:

90 mi / 65 mph = 1.4 hr

4 0
3 years ago
Round 2,329.48 to the nearest hundred
Nataly [62]

Answer:

Find the number in the hundred place  

3

and look one place to the right for the rounding digit  

2

. Round up if this number is greater than or equal to  

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and round down if it is less than  

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ANSWER: 2300

Step-by-step explanation:

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3 years ago
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#20. Choose the single logarithmic expression that is equivalent to the one shown.
Klio2033 [76]
My answer would be c. hope this helps.
6 0
4 years ago
3. Consider the sequence,-8, -5, -2, 1, ...
Naddik [55]

Answer:

a) a_n=3\,n-11

b) a_{20}=49

c) term number 17 is the one that gives a value of 40

Step-by-step explanation:

a)

The sequence seems to be arithmetic, and with common difference d = 3.

Notice that when you add 3 units to the first term (-80, you get :

-8 + 3 = -5

and then -5 + 3 = -2 which is the third term.

Then, we can use the general form for the nth term of an arithmetic sequence to find its simplified form:

a_n=a_1+(n-1)\,d

That in our case would give:

a_n=-8+(n-1)\,(3)\\a_n=-8+3\,n-3\\a_n=3n-11

b)

Therefore, the term number 20 can be calculated from it:

a_{20}=3\,(20)-11=60-11=49

c) in order to find which term renders 20, we use the general form we found in step a):

a_n=3\,n-11\\40=3\,n-11\\40+11=3\,n\\51=3\,n\\n=\frac{51}{3} =17

so term number 17 is the one that renders a value of 40

5 0
3 years ago
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