Question

Which of the following are solutions to the equation below?

Answer 1

Make it equal to zero
minus 6 from both sides
x^2+6x+3=0
quadratic formula
x=$\frac{-b+/- \sqrt{b^{2}-4ac} }{2a}$


x=$\frac{-6+/- \sqrt{6^{2}-4(1)(3)} }{2(1)}$
x=$\frac{-6+/- \sqrt{36-12} }{2}$
x=$\frac{-6+/- \sqrt{24} }{2}$
x=$\frac{-6+/- 2\sqrt{6} }{2}$
x=$-3+/- \sqrt{6}$


E and F are answer