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faltersainse [42]
3 years ago
11

The least common multiple of 2, 5, 6, and 9 is A. 60. B. 45. C. 90. D. 180.

Mathematics
2 answers:
ankoles [38]3 years ago
5 0
The least common multiple between those following numbers is C. 90.
erica [24]3 years ago
5 0
Lets do it by finding the L.C.M
 
         
<span> (2, 5, 6, 9)
divide the terms by two and leave those which are not divisible

2  (1,5,6,9)

</span><span>divide the terms by 3 and leave those which are not divisible
</span>
<span>2 x 3  (1,5,2,3)
</span>
<span>divide the terms by 3 again and leave those which are not divisible
</span>
2 x <span>3 x 3  (1,5,2,1)
</span>
<span>divide the terms by two and leave those which are not divisible
</span>

2 x <span>3 x 3 x 2 (1,5,1,1)
</span>
<span>divide the terms by five and leave those which are not divisible
</span>
2 x <span>3 x 3 x 2 x 5 (1,1,1,1)
</span>So the L.C.M is :

2 x <span>3 x 3 x 2 x 5=180
</span>so correct option is D 
hope it helps
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Answer:

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Step-by-step explanation:

Given equation:

-8+\sqrt{5a-5}=-3

Solving for unknown variable a

Adding 8 both sides by additive property of equality.

+8-8+\sqrt{5a-5}=-3+8

\sqrt{5a-5}=5

Squaring both sides to remove the square root.

(\sqrt{5a-5})^2=5^2

5a-5=25

Adding 5 both sides by additive property of equality.

5a-5+5=25+5

5a=30

Dividing both sides by 6 to isolate a

\frac{5a}{5}=\frac{30}{5}

∴ a=6

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Please help me I’ll mark you brainlyest.
Alenkasestr [34]

Answer:

10 and 7

Step-by-step explanation:

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strojnjashka [21]

There are two Right angled triangles in the given figure, with two missing sides, let's name the other missing side be " y "

According to Pythagoras theorem,

\boxed{ \large \boxed{h {}^{2}  =  {b}^{2} + p{}^{2}  }}

note :

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let's solve for " y² " first ( square of other missing side )

➢ \:  \:  {y}^{2}  =  {8}^{2}  + 3 {}^{2}

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now let's solve for " x " , by using pythagorous theorem

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