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3 years ago

Find the slope of the line through the two points below. (5,-1) and (0, 3)

Mathematics

1 answer:

Tcecarenko [31]3 years ago

8 0

Step-by-step explanation:

5--1/5-1 0+3/5-1=-5/4

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Lindsay deposited $2000 into a Roth IRA that grew to $5000 by retirement. If Lindsay is currently in the 10% tax bracket and ret

FromTheMoon [43]

0$ According to Apex F. Literacy

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3 years ago

Read 2 more answers

Simplify the expression (5 3i) (4-4i) a. 8i b. 9-i c. 9 i d. 9-7i

poizon [28]

The expression will be d. 9-7i

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3 years ago

7x² + 6x - 1<br> Algebra 3|factoring

GaryK [48]

Answer:

(7 x - 1) (x + 1)

Step-by-step explanation:

Factor the following:

7 x^2 + 6 x - 1

Factor the quadratic 7 x^2 + 6 x - 1. The coefficient of x^2 is 7 and the constant term is -1. The product of 7 and -1 is -7. The factors of -7 which sum to 6 are -1 and 7. So 7 x^2 + 6 x - 1 = 7 x^2 + 7 x - x - 1 = (7 x - 1) + x (7 x - 1):

(7 x - 1) + x (7 x - 1)

Factor 7 x - 1 from (7 x - 1) + x (7 x - 1):

Answer: (7 x - 1) (x + 1)

5 0

3 years ago

Against the wind a small plane flew 715 miles in 2 hours and 10 minutes. The return trip took only 1 hour and 50 minutes. What w

ZanzabumX [31]

Answer:

360 mi/h

Step-by-step explanation:

The speed for the outbound trip was ...

speed = distance/time = (715 mi)/(2 1/6 h) = 330 mi/h

The inbound speed was ...

(715 mi)/(1 5/6 h) = 390 mi/h

The airspeed of the plane is the average of these two ground speeds, so is ...

(330 +390)/2 = 360 . . . . mi/h

8 0

3 years ago

Find the distance of the point (3,4) from the midpoint of the line joining (8,10) and (4,6)

Elis [28]

Answer:

Distance between point $(3,4)$ and midpoint of line joining $(8,10)$ and $(4,6)$ = $5$ units.

Step-by-step explanation:

Given:

Points:

$A(3,4)\\B(8,10)\\C(4,6)$

To find distance from point A to midpoint of BC.

Midpoint M of BC:

$M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\$

$M=(\frac{8+4}{2},\frac{10+6}{2})\\$ [Plugging in points $B(8,10)\ and\ C(4,6)$ ]

$M=(\frac{12}{2},\frac{16}{2})\\$

$M=(6,8)\\$

Distance between A and M:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\$

$D=\sqrt{(6-3)^2+(8-4)^2} \\$ [Plugging in points $A(3,4)\ and\ M(6,8)$ ]

$D=\sqrt{(3)^2+(4)^2} \\$

$D=\sqrt{9+16} \\$

$D=\sqrt{25} \\$

$D=\pm5$

Since distance is always positive ∴ $D= 5$ units

4 0

3 years ago