The grams of Fe₂O₃ that are formed is 47.68 g
<u><em>calculation</em></u>
Step 1: write the equation for reaction
4 Fe +3O₂ → 2 Fe₂O₃
Step 2: find the moles of Fe
moles = mass÷ molar mass
= 33.4 g÷55.8 g/mol =0.5986 moles
Step 3 : use the mole ratio to determine the moles of Fe₂O₃
That is from equation above Fe:Fe₂O₃ is 4:2 therefore the moles of Fe₂O₃ is = 0.5986 moles x 2/4 =0.2993 moles
Step 4 : find the mass of Fe₂O₃
mass = mass x molar mass
The molar mass of Fe₂O₃ = (55.8 x 2 +(15.9 x3) = 159.3 g/mol
mass is therefore = 0.2993 moles x 159.3 g/mol =47.68 g
This is a strong base / week acid reaction.
NaOH + CH3COOH
The equilibrium of this reaction is very displaced to the right leading to the formation of the products
Na CH3COO + H2O
Na CH3COOH is a ionic compound which in solutionn will be as Na (+) and CH3COOH(-)
=> CH3COOH + NaOH = CH3 COO(-) + Na(+) + H2O
So, the predominant species in the solution are the ions Na(+) and CH3COO(-).
In general, in an strong base / weak acid titration, the predominant species present at the stoichiometric point will be the cation of the strong base (Na+ in this case) and the conjugate base of the weak acid (the anion of the weak acid, which is CH3COO- in this case).
The answer is predominantly Na(+) and CH3COO(-); predominantly because it is an equlibrium which means that the rectants will also br present.
False. The number of neutrons can be more or less than the number of protons.
Answer:
The answer is " salt".
Explanation:
Hey there!
When any acids and base react with eachother, they forms water and respective salts.
For example:
HCl + NAOH = NACl + H2O.
<em>Hope it helps!</em>
According to Henderson–Hasselbalch Equation,
pH = pKa + log [Acetate] / [Acetic Acid]
As,
pKa = -log Ka
pKa = -log (1.8 × 10⁻⁵)
pKa = 4.74
So,
pH = 4.74 + log [Acetate] / [Acetic Acid]
4.34 = 4.74 + log [Acetate] / [Acetic Acid]
4.34 - 4.74 = log [Acetate] / [Acetic Acid]
-0.40 = log [Acetate] / [Acetic Acid]
Taking Antilog on both sides,
[Acetate] / [Acetic Acid] = 0.398
