Question

A flexible container at an initial volume of 4.11 L contains 6.51 mol of gas. More gas is then added to the container until it reaches a final volume of 11.3 L. Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Answer 1

Answer:

The added mole will be "11.388 moles".

Explanation:

The given values are:

Initial volume,

V₁ = 4.11 L

Final volume,

V₂ = 11.3 L

Number of moles,

n₁ = 6.51

On applying Avogadro's law,

⇒  $\frac{V_{1}}{n_{1}}=\frac{V_{2}}{n_{2}}$

On putting the estimated values, we get

⇒  $\frac{4.11}{6.51} =\frac{11.3}{n_{2}}$

On applying cross-multiplication, we get

⇒  $4.11 \ n_{2}=11.3\times 6.51$

⇒  $4.11 \ n_{2}=73.563$

⇒  $n_{2}=\frac{73.563}{4.11}$

⇒  $n_{2}=17.898 \ moles$

So that the number of moles at added gas will be:

$=17.898-6.51$

$=11.388 \ moles$