Answer:
4.083 * 10^20 atoms.
Explanation:
One Mole of phosphorus contains 6.022 * 10^23 atoms (Avogadros number)'
Since 1 mole of Phosphorus has a mass of 30.974 grams, 21 milligrams has
6.022 * 10^23 * 0.021 / 30.974
= 0.004083 * 10^23
= 4.083 * 10^20
Except catalyst because catalyst typically speed up a reaction by reducing the activation energy or changing the reaction mechanism.
Answer:
The value of is 0.02495.
Explanation:
Initial concentration of gas = 0.675 M
Initial concentration of gas = 0.973 M
Equilibrium concentration of mustard gas = 0.35 M
initially
0.675 M 0.973 M 0
At equilibrium ;
(0.675-0.35) M (0.973-2 × 0.35) M 0.35 M
The equilibrium constant is given as :
The relation between and are :
where,
= equilibrium constant at constant pressure = ?
= equilibrium concentration constant =14.45
R = gas constant = 0.0821 L⋅atm/(K⋅mol)
T = temperature = 20.0°C =20.0 +273.15 K=293.15 K
= change in the number of moles of gas = [(1) - (1 + 2)]=-2
Now put all the given values in the above relation, we get:
The value of is 0.02495.