A. Fewer valence electrons
Valence electrons are electrons that are held most loosely in the outermost shell.
Idk if it's correct but I guess it's calcite (c)
Answer:
ΔH
°fCaO= -655.09 KJ/mol = ΔH
°fCaO
Explanation:
ΔH
°(reaction)a=ΔH
°f(product)-ΔH
°f(reactant)
where,
ΔH
°f(product)=is the standard heat of formation of products
-ΔH
°f(reactant)=is the standard heat of formation of reactants
The standard heat of formation of H
2
O
(
l
) is −
285.8
k
J
/
m
o
l
.
The standard heat of formation of Ca(OH
)2 is −
986.09
k
J
/
m
o
l
.
For the given reaction, the standard enthalpy change is calculated by the expression shown below.
ΔH
°(reaction)a=ΔH
°f(CaO+H2O)-ΔH
°f(Ca(OH)₂
65.2 = ΔH
°fCaO+( -265.8) -(-986.09)
= ΔH
°fCaO-265.8+986.09
65.2 = ΔH
°fCaO+ 720.29
65.2-720.29 = ΔH
°fCaO
-655.09 KJ/mol == ΔH
°fCaO
An ion is an atom or group of atoms in which the number of electrons is not equal to the number of protons, giving it a net positive or negative electrical charge.
Due to this, anoin which is a negatively charged and is attracted to the anode (positive electrode) in electrolysis. and is considered as a proton.
however Cations are positively charged and are attracted to cation ( negative electrode). its know as a electron .
So, the net positive or negative electrical charge explains the difference in the amounts of phosphate and strontium.
An ion can never have the same amount of anions and cations.
