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3 years ago

Determine the charge on each ion in the following compounds, and name the compound. Spelling counts!

Chemistry

2 answers:

34kurt3 years ago

7 0

1. Mg₃N₂: Magnesium nitride

charge Mg = +2

charge N = -3

2. Al₂S₃: Aluminum sulfide

charge Al = +3

charge S = -2

<h3>Further explanation</h3>

The naming of chemical compounds is giving a special name to a compound that aims to facilitate the classification of compounds and facilitate the identification of a compound. The rules for naming chemical compounds have been determined by the IUPAC (International Union of Pure and Applied Chemistry)

This nomenclature includes the naming of ion compounds, covalent compounds, and polyatomic

For ionic compounds consisting of cations (ions +) and anions (ions -)

The naming is preceded by the cation then the anion with the -ide suffix added

Generally for this ion compound consists of metal elements as cations and non-metals as anions

1. For metal and non-metal compounds

Metal: cation, positively charged.

Nonmetal: negative anion.

The anion cation's charge is crossed

Example:

Fe₂S₃

Fe charge = +3

S charge = -2

The name: metal + non-metal + -ide

Example: BaCl₂ -> Barium chloride

For transition metals, which have several oxidation charges / numbers, write the oxidation number in roman numbers

Example: SnO: lead (II) oxide

SnO₂: lead (IV) oxide

2. For metal and non-metal compounds

The naming: name non-metal + non-metal + suffix -ide

In the elements given the prefix mono, di, tri, tetra, penta if more than one element is formed

Example:

SO₂: Sulfur dioxide

SO₃: Sulfur trioxide

The question that needs to be completed is

Determine the charge on each ion in the following compounds, and name the compound. Spelling counts! (a) Mg₃N₂ Name: Charges: Mg N (b) Al₂S₃ Name: Charges: Al S

1. In the compound Mg₃N₂

load Mg = +2

charge N = -3

Name: Magnesium nitride

2. In the Al₂S₃ compound

Al load = +3

load S = -2

Name: Aluminum sulfide

<h3>Learn more</h3>

the chemical formula for each ionic compound.

brainly.com/question/11545331

two functional groups that contain ionic charges

brainly.com/question/1687047

Binary ionic compounds

brainly.com/question/2099598

Keywords: ionic compound, the naming of chemical compounds

lisabon 2012 [21]3 years ago

4 0

I can't really answer his if there is no given. However, there are general rules to follow when naming ionic compounds. For example, if the given compound is written as: MgCl₂.

There are two elements that we could find: Mg and Cl. The rule is to write the positive ion first, followed by the negative ion. The individual charges of each element is the subscript of the other. Since Cl has a subscript of 2, then Mg has a charge of +2. Since Mg has a subscript of 1, then Cl has a charge of -2.

Finally, the rule of naming the ionic compound is to name the ions individually in order, but you have to take the suffix -ide (if the charge is -1). Thus, the name of the compound is Magnesium Chloride,

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A block of metal has a width of 3.2 cm , a length of 17.1 cm , and height of 4.6 cm . Its mass is 1.4 kg . Calculate the density

dsp73

The Density of the metal is 5.6 g/cm³

<h3>What is the density of a substance?</h3>

The density of a substance is the ratio of the mass and the volume of the substance.

Density = mass/volume

The density of the metal is calculated as follows:

mass of metal = 1.4 kg = 1400 g

volume of metal = 3.2 * 17.1 * 4.6 = 251.712 cm³

Density of metal = 1400 g/251.712 cm³

Density of the metal = 5.6 g/cm³

Therefore, the density of the metal is obtained from the mass and the volume of the metal.

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2 years ago

How is a gas's ability to fill a container different from that of a liquid or a solid?

svp [43]

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8 0

3 years ago

The equilibrium constant for the reaction

FinnZ [79.3K]

Answer: The concentrations of $Cl_2$ at equilibrium is 0.023 M

Explanation:

Moles of $Cl_2$ = $\frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol$

Volume of solution = 1 L

Initial concentration of $Cl_2$ = $\frac{0.14mol}{1L}=0.14M$

The given balanced equilibrium reaction is,

$COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)$

Initial conc. 0.14 M 0 M 0M

At eqm. conc. (0.14-x) M (x) M (x) M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}$

Now put all the given values in this expression, we get :

$4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}$

By solving the term 'x', we get :

x = 0.023 M

Thus, the concentrations of $Cl_2$ at equilibrium is 0.023 M

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3 years ago

Give the empirical formula for C↓8H↓8

mr_godi [17]

Answer:

Empirical formula of C₈H₈ = CH

Explanation:

Data Given:

Molecular Formula = C₈H₈

Empirical Formula = ?

Solution

Empirical Formula:

Empirical formula is the simplest ration of atoms in the molecule but not all numbers of atoms in a compound.

So,

tha ration of the molecular formula should be divided by whole number to get the simplest ratio of molecule

C₈H₈ Consist of Carbon (C), and Hydrogen (H)

Now

Look at the ratio of these two atoms in the compound

C : H

8 : 8

Divide the ratio by two to get simplest ratio

C : H

8/8 : 8/8

1 : 1

So for the empirical formula is the simplest ratio of carbon to hydrogen 1 : 1

So the empirical formula will be

Empirical formula of C₈H₈ = CH

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horrorfan [7]

Answer:

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Explanation:

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