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lukranit [14]
3 years ago
14

Determine the charge on each ion in the following compounds, and name the compound. Spelling counts!

Chemistry
2 answers:
34kurt3 years ago
7 0

1. Mg₃N₂: Magnesium nitride

charge Mg = +2

charge N = -3

2. Al₂S₃: Aluminum sulfide

charge Al = +3

charge S = -2

<h3>Further explanation</h3>

The naming of chemical compounds is giving a special name to a compound that aims to facilitate the classification of compounds and facilitate the identification of a compound. The rules for naming chemical compounds have been determined by the IUPAC (International Union of Pure and Applied Chemistry)

This nomenclature includes the naming of ion compounds, covalent compounds, and polyatomic

For ionic compounds consisting of cations (ions +) and anions (ions -)

The naming is preceded by the cation then the anion with the -ide suffix added

Generally for this ion compound consists of metal elements as cations and non-metals as anions

  • 1. For metal and non-metal compounds

Metal: cation, positively charged.

Nonmetal: negative anion.

The anion cation's charge is crossed

Example:

Fe₂S₃

Fe charge = +3

S charge = -2

The name: metal + non-metal + -ide

Example: BaCl₂ -> Barium chloride

For transition metals, which have several oxidation charges / numbers, write the oxidation number in roman numbers

Example: SnO: lead (II) oxide

SnO₂: lead (IV) oxide

  • 2. For metal and non-metal compounds

The naming: name non-metal + non-metal + suffix -ide

In the elements given the prefix mono, di, tri, tetra, penta if more than one element is formed

Example:

SO₂: Sulfur dioxide

SO₃: Sulfur trioxide

The question that needs to be completed is

Determine the charge on each ion in the following compounds, and name the compound. Spelling counts! (a) Mg₃N₂ Name: Charges: Mg N (b) Al₂S₃ Name: Charges: Al S

1. In the compound Mg₃N₂

load Mg = +2

charge N = -3

Name: Magnesium nitride

2. In the Al₂S₃ compound

Al load = +3

load S = -2

Name: Aluminum sulfide

<h3>Learn more</h3>

the chemical formula for each ionic compound.

brainly.com/question/11545331

two functional groups that contain ionic charges

brainly.com/question/1687047

Binary ionic compounds

brainly.com/question/2099598

Keywords: ionic compound, the naming of chemical compounds

lisabon 2012 [21]3 years ago
4 0
I can't really answer his if there is no given. However, there are general rules to follow when naming ionic compounds. For example, if the given compound is written as: MgCl₂. 

There are two elements that we could find: Mg and Cl. The rule is to write the positive ion first, followed by the negative ion. The individual charges of each element is the subscript of the other. Since Cl has a subscript of 2, then Mg has a charge of +2. Since Mg has a subscript of 1, then Cl has a charge of -2.

Finally, the rule of naming the ionic compound is to name the ions individually in order, but you have to take the suffix -ide (if the charge is -1). Thus, the name of the compound is Magnesium Chloride,
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What volume of 7.25 mol/L stock solution in needed to make 3.84 L of 8.50 mol/L solution?
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Explanation:

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Now, keeping in mind that

  • Concentration = Mol / Volume

we can calculate the volume of a 7.25 mol/L solution that would contain 32.64 moles:

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Considering the volumes and the concentrations used in mixture 1, what percentage of the moles of H2O2 present have been consume
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Answer:

1 mol of H2O2 consumes 1 mol of S2O32, then 0.0005 mol of I- reacts with 0.00025 moles of H2O2

Thus, initial moles of H2O2 present in the mix is equal to 0.0102 moles.

Amount of moles of H2O2 that reacts with I- is equal to 0.00025 moles.

The amount of I ions that is oxidized by H2O2 and the iodine, I2 that is produced, is consumed by the S2O32- ions and are transformed into I ions. The amount of I ions that are consumed by H2O2 is equal to the amount of ion that is produced by S2O32-.

Explanation:

the total volume of the mixture is equal to:

Vmix = 75 + 30 + 25 + 5 + 5 + 10 = 150 mL

the moles of each species in the mix equals:

Na2S2O3 = 0.05 * 0.005 = 0.00025 moles

KI = 0.05 * 0.025 = 0.00125 moles

H2O2 = 1.02 * 0.01 = 0.0102 moles

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I2 + S2O32 = 2I- + S4O62-

The same way:

2I- + 2H+ + H2O2 = I2 + 2H2O

1 mol of H2O2 consumes 1 mol of S2O32, then 0.0005 mol of I- reacts with 0.00025 moles of H2O2

Thus, initial moles of H2O2 present in the mix is equal to 0.0102 moles.

Amount of moles of H2O2 that reacts with I- is equal to 0.00025 moles.

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