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Show that the points A (-3, 2), B (-6, 4) and C (1, 8) are vertices of a right triangle.
1 answer:
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Answer:
Step-by-step explanation:
When we solve for an equation, our goal is to find the value of the variable. Any variable can be used, but for the time being let’s assume we use .
We can algebraeically solve equations until we get the value of x - in which we will have x equal to something.
Say we have the equation . Our goal is to find the value of
. <u>We can do this by getting x isolated on one side so we have something equal to x</u>.
We can subtract 5 from both sides and divide both sides by 5.
We now know the value of since it’s on one side of the equation.
Hope this helped!
Answer:
90°, 60°, and 30°
60°.
Step-by-step explanation:
The triangle ABC has side lengths √6, √2, and 2√2 units.
It is clear that the triangle ABC is right triangle because (2√2)² = (√6)² + (√2)² that means the side lengths satisfy the Pythagoras Theorem.
Now, if the angle between hypotenuse (2√2 units) and base (√2 units) is , then
Hence, = 60°
Therefore, the three angles of the triangle are 90°, 60°, and 30°.
Now, if the base of the triangle is 16 units, then other two side lengths will also change proportionally to remain the triangle a right triangle.
And in that case the base angle will remain 60°. (Answer)