Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.
What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So
has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Answer:
The solution of the given equations is (-3,2)
Step-by-step explanation:
<u>Step:1</u>
The Given equations are 2 x+3 y=0 .......(1)
x+2 y-1 =0.........(2)
<u>Step 2:-</u>
Solving<u> </u>both equations by using substitution method
multiply equation (2) with number '2' ,
2 x+4 y-2=0.......(3)
subtracting the equations (1) and (3) and cancelled 'x' terms
we get 
<u>Step 3:</u>-
substitute y= 2 in equation (1) we get
<u>Final answer</u>:-
The solution of the given equations is (-3,2)
Answer:
$750
Step-by-step explanation:
Larger share = $450
Smaller share : Larger share :: 2 : 3
Smaller share = (larger share x 2) / 3
= (450x2)/3
= 300
Sum= larger share + smaller share
= $450 + $300 = $750
Answer:
As mentioned in the explanation steps.
Step-by-step explanation:
The following theorem is helpful to prove that the alternate exterior angles are congruent.
If two lines lie in the same plane and parallel to each other. A traversal line intersect these parallel lines at different points, then the alternate exterior angles must be same.
