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Lapatulllka [165]
3 years ago
8

6) 0.5334 how do I show my work ​

Mathematics
1 answer:
Goshia [24]3 years ago
3 0

Answer:

Step-by-step explanation                              if u know how  to use standered algorithim just divide the same way you divided  p.s the answer is 11.2485939258 .

You might be interested in
Y=3x-8 in function notation
julia-pushkina [17]

To write it in function notation you'll convert it into a function, substituting y by f(x):


y = 3x - 8 = f(x) = 3x - 8



Hope it helped,



BioTeacher101

3 0
3 years ago
On the blueprint of a house, 36 millimeters represents 7 meters. The length of the living room is 27 millimeters on the blueprin
S_A_V [24]
36/27=1.3
7x1.3=9.1
The actual length is 9.1meters
7 0
3 years ago
Help me Solve 1/6 ÷ 2/6 please
pochemuha
\frac{1}{6} ÷ \frac{2}{6}

First, apply this following rule: a ÷ \frac{b}{x} = a × \frac{c}{b}
\frac{1}{6} × \frac{6}{2}
Second, apply this following rule: \frac{a}{b} × \frac{c}{d} =  \frac{ac}{bd}
\frac{1x6}{6x2}
Third, multiply 1 × 6 to get 6 and 6 × 2 to get 12.
\frac{6}{12}
Fourth, find the GCF of 6 and 12. 
Factors of 6: 1, 2, 3, 6
Factors of 12: 1, 2, 3, 4, 6, 12
The GCF is 6.
Fifth, divide the numerator by the GCF.
6 ÷ 6 = 1
Sixth, divide the denominator by the GCF.
12 ÷ 6 = 2
Seventh, collect the new numerator and new denominator.
\frac{1}{2}

Answer as fraction: \frac{1}{2}
Answer as decimal: 0.5

8 0
3 years ago
Don’t answer if you don’t know, plz. Thanks.
horrorfan [7]
B. I did this test too.
7 0
2 years ago
In order to estimate the average electric usage per month, a sample of 81 houses was selected and the electric usage was determi
lana [24]

Answer:

Confidence interval:  (1760,1956)

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 81

Sample mean =

\bar{x} = 1858 \text{ kWh}

Population standard deviation =

\sigma = 450 \text{ kilowatt-hours}

Confidence Level = 95%

Significance level = 5% = 0.05

Confidence interval:

\bar{x} \pm z_{critical}\displaystyle\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96

1858 \pm 1.96(\displaystyle\frac{450}{\sqrt{81}} ) = 1858 \pm 98 = (1760,1956)

6 0
3 years ago
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