Question

Solve In 2x + In 2=0​

Answer 1

Solving  $ln(2x)+ln(2)=0$ we get, $x=\frac{1}{4}$

Step-by-step explanation:

We need to solve: $ln(2x)+ln(2)=0$

Solving:

$ln(2x)+ln(2)=0$

Adding -ln(2) on both sides:

$ln(2x)+ln(2)-ln(2)=0-ln(2)$

$ln(2x)=-ln(2)$

Using logarithmic rule: if $log_a b =c\,\,then\,\, b=a^c$

So,

$2x=e^{-ln(2)}$

Simplifying:

$2x=(e^{ln(2)})^{-1}\\e^{ln(2)}=2\\2x=(2)^{-1}\\2x=\frac{1}{2} \\x=\frac{1}{2x2}\\x=\frac{1}{4}$

So, Solving  $ln(2x)+ln(2)=0$ we get, $x=\frac{1}{4}$

Keywords: Logarithms

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