The probability that a student participates in both sports and drama is
.
<h3>What is the formula for P(AUB), where A and B are any two events?</h3>
If
and
are any two events, then the probability of the joint event
is given by the following formula: 
Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.
Suppose
denotes that "a student participates in sports" and
denotes that "a student participates in drama".
So, we have
,
,
.
We want to find the probability that a student participates in both sports and drama i.e., we want to find
.
By the above formula, we obtain:

Therefore, the probability that a student participates in both sports and drama is
.
To learn more about probability, refer: brainly.com/question/24756209
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