Answer:
The correct answers are 2.23 * 10^8 CFU/ml and 2 colonies.
Explanation:
Based on the given information, 0.1 ml is the amount of bacterial culture plated, 10^-5 is the dilution factor and the number of bacterial colonies produced is 223.
A) 223 is the number of colonies produced when 0.1 ml of the culture is plated. Therefore, the number of colonies produced when 1 milliliter of bacterial culture plated us (223/0.1)*1 = 2230
The calculation of the CFU/ml is done by using the formula,
CFU/ml = Number of colonies per ml plated / dilution factor
Thus, 2230/10^-5
= 2230 * 10^5 or 2.23 * 10^8 CFU/ml
B) The number of colonies, which would grow on a plate, which is inoculated with 0.1 ml volume of 10^-7 dilution from the similar bacterial stock will be calculated as,
CFU/ml = Number of colonies per ml plated/ dilution * volume plated.
2.23 * 10^8 CFU/ml = Number of colonies per ml plated / 10^-7 * 0.1
Number of colonies per ml plated = 2.23 * 10^8 * 0.1 / 10^7 = 2.23 or 2 colonies.
Hydrophobic and hydrophilic bond/interactions are common bond that forms long chains of proteins.
Some complex forms of proteins are made of subunits in which molecules bond together to form a larger unit. A good example is the blood protein hemoglobin. Hemoglobin consists of protein subunits known as the globin molecules. These subunits are folded chains of a large number of different amino acids which are known as polypeptides.
Answer:
B. Smaller and more mobile gametes
Explanation:
Answer:
I'm not sure but I think it should be the enzyme inhibitor binds to the products of the reaction which makes the enzyme unproductive
Explanation:
By binding to enzymes' active sites, inhibitors reduce the compatibility of substrate and enzyme and this leads to the inhibition of Enzyme-Substrate complexes' formation, preventing the catalyzation of reactions and decreasing (at times to zero) the amount of product produced by a reaction. It can be said that as the concentration of enzyme inhibitors increases, the rate of enzyme activity decreases, and thus, the amount of product produced is inversely proportional to the concentration of inhibitor molecules. Since blocking an enzyme's activity can kill a pathogen or correct a metabolic imbalance, many drugs are enzyme inhibitors. The binding of an inhibitor can stop a substrate from entering the enzyme's active site and/or hinder the enzyme from catalyzing its reaction. Inhibitor binding is either reversible or irreversible. Irreversible inhibitors usually react with the enzyme and change it chemically (e.g. via covalent bond formation).
Answer:
The correct answer is B. The virus can infect the host.
Explanation:
- As the host and the virus both remain in the agar plate, the virus is capable of infecting the host cells.
- The host cell multiplies and grows by utilising the nutrient from the agar medium.
- After the virus particles infect the host, they replicate inside the host and produce new progeny virions which get released out of the host cell by killing it.
- The newly formed virions infect other host cells and the process continues.
- The killing of the host cells by the viruses result in the generation of clear zones on the agar plate which is also known as the zone of exclusion.
- In the zone of exclusion region, the host cells have been killed by the viruses.
