Question

Suppose a triangle has two sides of length 2 and 3 and that angle between these two sides is 60 degrees. What is the length of the third side

Answer 1

Answer:

The measure of the third side is $\sqrt{7}\ units$

Step-by-step explanation:

we know that

Applying the law of cosines

$c^2=a^2+b^2-2(a)(b)cos(C)$

where

C is the angle between side a and side b

we have

$a=2\ units\\b=3\ units\\C=60^o$

substitute

$c^2=2^2+3^2-2(2)(3)cos(60^o)$

$c^2=13-(12)(\frac{1}{2})$

$c^2=13-6$

$c^2=7$

$c=\sqrt{7}\ units$