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mrs_skeptik [129]
4 years ago
14

Help!!!!! please!!!!!

Mathematics
2 answers:
Nostrana [21]4 years ago
7 0

Hey there! :)

Answer:

Choice D. V = 2184 in³.

Step-by-step explanation:

Recall that to find the volume of a rectangular prism, the following formula is used:

V = l × w × h

Plug in the given dimensions into the formula to solve for the volume:

V = 14 × 13 × 12

Multiply:

V = 2184 in³. The correct answer is D.

hichkok12 [17]4 years ago
6 0

Answer:

2,184 inches^3

Step-by-step explanation:

Well to find the volume of a rectangular prism we have to use the following formula l*w*h.

The l is length which is 14 the w which is width which is 13, and the h which is height which is 12.

So we do 14*12*13 which is 2,184 inches^3.

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4 years ago
Solving multi step equations
hichkok12 [17]

The no-brain way to do it is to

  1. subtract one side from both sides so you have <em>(something) = 0</em>.
  2. divide by the coefficient of the variable.
  3. add the opposite of the constant.

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... ax + b = 0 . . . . . . where <em>a</em> and <em>b</em> are some constants that may be positive or negative

17) Subtract the right side.

... 10(x +3) -(-9x -4) -(x -5 +3) = 0

... 10x + 30 +9x +4 -x +5 -3 = 0 . . . . . eliminate parentheses

... x(10+9-1) +(30+4+5-3) = 0 . . . . . . . collect terms

... 18x +36 = 0 . . . . . . . . . . . . . . . . . . . simplified

... x + 2 = 0 . . . . . . . . . . . . . . . . . . . . . .divide by 18, the coefficient of x

... x = -2 . . . . . . . . . . . . . . . . . . . . . . . . add the opposite of the constant

19) Add the opposite of the left side.

... 0 = -9(1 +7x) +12(x -12)

... 0 = -9 -63x +12x -144 . . . . . . eliminate parenthses

... 0 = -51x -153 . . . . . . . . . . . . . simplify

... 0 = x +3 . . . . . . . . . . . . . . . . . divide by -51, the coefficient of x

... -3 = x . . . . . . . . . . . . . . . . . . . add the opposite of the constant

_____

If you examine the variable's coefficients you can make a choice of side to subtract that results in a positive coefficient of the variable.

This method puts variable and constant together until the end. The approach usually taught is to separate the variable terms and constant terms. (The number of steps required is the same either way.)

The reason this is "no brain" is that it always works and requires no judgment as to what you add or subtract from where. Applying a little judgment as described above can make it so you're mostly working with positive numbers, but the method works whether the numbers are positive or negative.

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