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WARRIOR [948]
3 years ago
14

if you are 15 years old now, which equation could be used to solve for your age, y, 12 years from now ?

Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

Answer:

Hi there!

If you are 15 right now, you would use the expression: 15+12=y

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Write as a unit rate: Four notebooks for $2.50
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Answer:

B. $1.60 per notebook

Step-by-step explanation:

Because:

4 notebooks ÷ $2.50 (4 notebooks cost) = $1.60 per notebook

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3 years ago
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Find the area of the blue sector(s). The diameter is 14.
pav-90 [236]

The area of the entire circle is pi*(7)^2, or 49pi.


Due to the 90 degree angle, the area of the larger blue sector is


90

------- * 49 pi = 49/4 units^2

360


The area of the smaller blue sector is


48

------- 49 pi = (2/15)(49 pi) = 98 pi/15 units^2

360


The total area of the blue sectors is the sum of 98 pi/15 and 49 pi/4 (units^2):


59 units^2

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3 years ago
What is the greatest common factor of 10 and 50
brilliants [131]
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How do you solve -50x3/1000
Finger [1]

Answer:

-.15

Step-by-step explanation:

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7 0
3 years ago
|1/2b-8|=|1/4b-1|<br> b=____ and ____
Deffense [45]

Answer:

  b = 12 and 28

Step-by-step explanation:

The absolute value equation |1/2b-8| = |1/4b-1| resolves to a piecewise linear function with three pieces. There are two solutions.

<h3>Domains</h3>

The absolute value function on the left has a turning point where its value is zero:

  1/2b -8 = 0

  b -16 = 0

  b = 16

The absolute value function on the right has a turning point where its value is zero:

  1/4b -1 = 0

  b -4 = 0

  b = 4

For b > 16, both absolute value functions are identity functions. In this domain, the equation is ...

  1/2b -8 = 1/4b -1

For 4 < b < 16, the function on the left negates its argument, so the equation in this domain is ...

  -(1/2b -8) = 1/4b -1

For b < 4, both functions negate their arguments, so the equation in this domain is ...

  -(1/2b -8) = -(1/4b -1)

For the purpose of finding the value of b, this is effectively identical to the equation for b > 16. (The value of b does not change if we multiply both sides of the equation by -1.)

<h3>Solutions</h3>

<u>Domain b < 4 ∪ 16 < b</u>

  1/2b -8 = 1/4b -1

  2b -32 = b -4 . . . . . . . . multiply by 4

  b = 28 . . . . . . . . . . . . add 32-b to both sides

This solution is in the domain of the equation, so is one of the solutions to the original equation.

<u>Domain 4 < b < 16</u>

  -(1/2b -8) = 1/4b -1 . . . . equation in this domain

  -2b +32 = b -4 . . . . . . multiply by 4

  36 = 3b . . . . . . . . . . . add 2b+4 to both sides

  12 = b . . . . . . . . . . . . divide by 3

This solution is in the domain of the equation, so is the other solution to the original equation.

<h3>Graph</h3>

For the purposes of the graph, we have define the function g(b) to be the difference of the two absolute value functions. The solutions are found where g(x) = 0, the x-intercepts. The graph shows those to be ...

  b = 12  and  b = 28

__

<em>Additional comment</em>

Defining g(b) = |1/2b-8| -|1/4b-1|, we can rewrite it as ...

  g(b)=\begin{cases}7-\dfrac{1}{4}b&\text{for }b < 4\\-\dfrac{3}{4}b+9&\text{for }4\le b < 16\\\dfrac{1}{4}b-7&\text{for }16\le b\end{cases}

Then the solutions are the values of b that make g(b) = 0.

4 0
2 years ago
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