Simplify.
1 answer:
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Answer:
Consider the following calculations
Step-by-step explanation:
The complete R snippet is as follows
install.packages("Sleuth3")
library("Sleuth3")
attach(case0502)
data(case0502)
## plot
# plots
boxplot(Percent~ Judge, data=case0502,ylab="Values",
main="Boxplots of the Data",col=c(2:7,8),horizontal=TRUE)
# perform anova analysis
a<- aov(lm(Percent~ Judge,data=case0502))
#summarise the results
summary(a)
### we can use the independent sample t test here
sp<-case0502[which(case0502$Judge=="Spock's"),]
nsp<-case0502[which(case0502$Judge!="Spock's"),]
## perform the test
t.test(sp$Percent,nsp$Percent)
The results are CHECK THE IMAGE ATTACHED
b)
> summary(a)
Df Sum Sq Mean Sq F value Pr(>F)
Judge 6 1927 321.2 6.718 6.1e-05 *** as the p value is less than 0.05 , hence there is a significant difference in the percent of women included in the 6 judges’ venires who aren’t Spock’s judge
Residuals 39 1864 47.8
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
c)
t.test(sp$Percent,nsp$Percent)
Welch Two Sample t-test
data: sp$Percent and nsp$Percent
t = -7.1597, df = 17.608, p-value = 1.303e-06 ## as the p value is less than 0.05 , hence we reject the null hypothesis in favor of alternate hypothesis and conclude that there is a significant difference in the percent of women incuded in Spock’s venires versus the percent included in the other judges’ venires combined
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-19.23999 -10.49935
sample estimates:
mean of x mean of y
14.62222 29.49189
Answer: The below figure shows the graph of the given situation.
Step-by-step explanation:
Since, at first Caroline has brownies= 48
And, according to the question, it is decreasing by 6 per hour.
Then, the function of the given situation can be written as,
f(x)=48 - 6 x, ------ (1)
where, x is the number of hours and f(x) is the number of brownies Caroline has left in x hour.
Thus by substitution x= 0,1,2,3,4,5,6,7,8 in equation (1),
We get, f(x)=48, 42, 36, 30, 24, 18, 12, 6, 0
So, the function has points, (0, 48), (1, 42), (2, 36), (3, 30), (4, 24), (5,18 ),(6,12 ) (7, 6) (8, 0).
With help of the above points we can draw the graph of the given situation.
Note: since at x=8, f(x)=0 therefore after 8 hours she has no brownies left.
