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babymother [125]
3 years ago
15

Your older brother turned 35 today, and he is planning to save $7,000 per year for retirement, with the first deposit to be made

one year from today. He will invest in a mutual fund that's expected to provide a return of 7.5% per year. He plans to retire 30 years from today, when he turns 65, and he expects to live for 25 years after retirement, to age 90. Under these assumptions, how much can he spend each year after he retires?
Business
1 answer:
erik [133]3 years ago
6 0

Answer:

Elder Brother will be able to annual spend $64,932.21 each year for 25 years after retirement.

Explanation:

The question is to find the Future Value of saving $7,000 per year for retirement.

First step is to know the formula for the Future of Annuity in order to compute the future value of his yearly deposits.

<h2>Future Value (FV) = P * (1+r)^{n}- 1/r]</h2>

FV= Future value of the annuity

P= The annual payments/savings

r = rate for each period

n= number of years he is to save

FV = $7,000 * (1+0.075)^{30}- 1/0.075]

= $7,000 x (8.754955-1/0.075

=$7,000 x (7.754955/0.075)

= $723,795.82

The answer above shows the amount of cash flow, his current yearly savings will make available for him at the age of 65 and to be spent for the 25 years he expects to live after retirement.

Using the amount therefore, we can determine the amount he is able to spend each year as follows

PV (at the time of his retirement)= P x [1-(1+r)^{-n}/r]

Where PV= $723,795.82

P= Expected periodic spending per year after retirement

R = Rate for each period = 7.5%

n= number of years expected after retirement= 25 years

$723,795.82= P x [1-(1+0.075)^{-25}/0.075]

$723,795.82= P [(1-0.163979)/0.075]

$723,795.82= P x (0,836021 /0.075)

$723,795.82= P x 11.14695

P= $723,795.82=/11.14695

P= $64,931.21

This means Elder Brother will be able to annual spend $64,932.21 each year for 25 years after retirement.

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Answer:

Suppose the cost per hour incurred in operating a cruise ship is 3a + b v^{2}dollars per hour, where a and b are positive constants and v is the ship's speed in miles per hour. At what speed (in miles per hour) should the ship be operated between two ports, at a distance D miles apart, to minimize the cost? (Hint: Minimize the cost, not the cost per hour.)

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The problem can be solved using differentiation to get the minimum value of the speed to travel between the two ports. Step by step calculation is contained in the attached images;

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3 years ago
A 60,000 square meter rectangular yard is to be enclosed on three sides by wood fencing that costs $25.00 per meter and on the f
raketka [301]

Answer:

C'(y) = 50 -\frac{3900000}{y^2}=0

And we can solve for y and we got:

y = \sqrt{\frac{3900000}{50}}= 279.285

And using condition (1) we can solve for x and we got:

x= \frac{60000}{279.285}= 214.834

So then the minimum cost for this case would be:

C = 50*279.285 + 65*214.834 = 27928.49

Explanation:

For this case the graph attached illustrate the problem for this case

We know that the total area is 60000, so then we have:

xy = 60000

If we solve for x we got:

x = \frac{60000}{y}  (1)

Now we can define the cost function like this:

C = 2*(25)*y + 25 x +40 x

C(x,y) = 50 y + 65 x

We can use the condition (1) and if we replace in the cost function we have:

C(y) = 50 y + 65(\frac{60000}{y})

Since we need to minimize the cost, we can derivate the function in terms of y and we got:

C'(y) = 50 -\frac{3900000}{y^2}=0

And we can solve for y and we got:

y = \sqrt{\frac{3900000}{50}}= 279.285

And using condition (1) we can solve for x and we got:

x= \frac{60000}{279.285}= 214.834

So then the minimum cost for this case would be:

C = 50*279.285 + 65*214.834 = 27928.49

7 0
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