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nlexa [21]
3 years ago
13

Through how many volts of potential difference must an electron, initially at rest, be accelerated to achieve a wave length of 0

.27nm? A) 4.6 V
B) 0.046 V
C) 0.27 V
D) 4.6 MV
E)4.6 kV
Physics
1 answer:
deff fn [24]3 years ago
4 0

Answer:

20.7 volts

Explanation:

m = mass of electron = 9.1 x 10⁻³¹ kg

λ = wavelength of electron = 0.27 x 10⁻⁹ m

v = speed of electron

Using de-broglie's hypothesis

λ m v = h

(0.27 x 10⁻⁹) (9.1 x 10⁻³¹) v = 6.63 x 10⁻³⁴

v = 2.7 x 10⁶ m/s

ΔV = Potential difference through which electron is accelerated

q = charge on electron = 1.6 x 10⁻¹⁹ C

Using conservation of energy

(0.5) m v² = q ΔV

(0.5) (9.1 x 10⁻³¹) (2.7 x 10⁶)² = (1.6 x 10⁻¹⁹) ΔV

ΔV = 20.7 volts

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Answer:

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f = c/λ

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v0 is your speed, this is what we want to find.

Replacing those quantities in the equation, we get:

(3*10^17nm/s)/550 = (3*10^8 m/s + v0)/(3*10^8 m/s)*(3*10^17nm/s)/650 nm

(650nm)/(550nm) = (3*10^8 m/s + v0)/(3*10^8 m/s)

1.182*(3*10^8 m/s) = (3*10^8 m/s + v0)

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