Explanation :
The full form of SONAR is Sound Navigation and Ranging. It consists of a transmitter and a detector. This effect is used to find the depth of the sea and to know the location of submarines, valleys etc.
The ultrasonic waves move through the water. It strikes the sea bed and reflected back. The detectors detect it.
Let the speed of sound in seawater is v and it takes t time in the transmitting and receiving ultrasonic waves. The total distance in transmitting and receiving signal is 2d.
So,
Hence, the given figure works on the principle of SONAR.
Answer: Option B: 1.3×10⁵ W
Explanation:
Work Done,
Where s is displacement in the direction of force and F is force.
where, v is the velocity.
It is given that, F = 5.75 × 10³N
v = 22 m/s
P = 5.75 × 10³N×22 m/s = 126.5 × 10³ W ≈1.3×10⁵W
Thus, the correct option is B
Answer:
A) 0.660 g/ml
B) 1.297 ml
C) 0.272 g
Explanation:
Every substance, body or material has mass and volume, however the mass of different substances occupy different volumes. This is where density appears as a physical characteristic property of matter that establishes a relationship between the mass
of a body or substance and the volume
it occupies:
(1)
Knowing this, let's begin with the answers:
<h2 /><h2>Answer A:</h2>Here the mass is and th volume
Solving (1) with these values:
(2)
(3)
In this case the mass of a sample is and its density is
.
Isolating from (1):
(4)
(5)
(5)
In this case the volume of a sample is and its density is
.
Isolating from (1):
(6)
(7)
(8)
Answer:
mass of the neutron star =3.45185×10^26 Kg
Explanation:
When the neutron star rotates rapidly, a material on its surface to remain in place, the magnitude of the gravitational acceleration on the central material must be equal to magnitude of the centripetal acc. of the rotating star.
That is
M_ns = mass odf the netron star.
G= gravitational constant = 6.67×10^{-11}
R= radius of the star = 18×10^3 m
ω = 10 rev/sec = 20π rads/sec
therefore,
= 3.45185... E26 Kg
= 3.45185×10^26 Kg