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koban [17]
3 years ago
13

How do you use a number line to compare inequalitys

Mathematics
1 answer:
mezya [45]3 years ago
3 0
Graphing an inequality on a number line, is very similar to graphing a number. For instance, look at the top number line x = 3. We just put a little dot where the '3' is, right?

Now an inequality uses a greater than, less than symbol, and all that we have to do to graph an inequality is find the the number, '3' in this case and color in everything above or below it.

Just remember
if the symbol is (≥ or ≤) then you fill in the dot, like the top two examples in the graph below
if the symbol is (> or <) then you do not fill in the dot like the bottom two examples in the graph below
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NeX [460]
(4/9)/x = 12
(4/9) = 12x
Divide both sides by 12
(1/27) =x
7 0
2 years ago
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6 Paul runs 1.5 km on the bearing 127°. a Draw a diagram of the situation. b How far east is Paul from his starting point? ( How
GenaCL600 [577]

By running in a bearing of 127°, Paul motion is in the south eastern direction.

Correct responses:

a. Please find attached the required diagram created with MS Visio

b. Paul's distance travelled east is approximately 11.98 km

  • Paul's distance travelled south is approximately 0.903 km

<h3>Method used for diagram and for the distance calculation</h3>

Given:

The distance Paul runs = 1.5 km

The bearing Paul is running = 127°

a. The bearing of path Paul runs, 127°, is the angle measured in the clockwise direction relative to the northern direction

Please find attached the diagram representing the situation, created with MS Visio.

b. Paul's distance travelled east relative to the starting point is given by the component of Paul's path in the x-axis direction which is found as follows;

  • Paul's distance east =  15 km × cos(37°) ≈ <u>11.98 km</u>

Pau's distance travelled in the south direction relative to the starting point

is given by the vertical distance travelled relative to the x-axis, which is

given as follows;

Distance Paul travels south = 1.5 km × sin(37°) ≈ <u>0.903 km</u>

Learn more about bearings in trigonometry here:

brainly.com/question/23427938

5 0
2 years ago
2r^2+3s^3-r^2+4t^2-r^2 if r=-2, s=-3, and t=5
dimulka [17.4K]
2(-2)^2+3(-3)^3-(-2)^2+4(5)^2-(-2)^2 = 19

19 is the answer.
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3 years ago
Help i need it badly
ser-zykov [4K]

Answer:

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Answer:

18.6 minutes

Step-by-step explanation:

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