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suter [353]
2 years ago
11

Kevin finished a race in 25.7 minutes juile finished the race 7 1/10 sooner than kevin finished it how many minutes did it take

juile to finish
Mathematics
1 answer:
Papessa [141]2 years ago
5 0

Answer:

18.6 minutes

Step-by-step explanation:

subtract. im sorry if this is not right. im not smart

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Which following figures have a area of 64 square feet? Select three that apply
Korvikt [17]

Answer:

<em><u>a,e and b</u></em>

Step-by-step explanation:

8 0
2 years ago
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Solution to 3x+2y=24
seropon [69]

Answer:

it’s a multi step equation

Step-by-step explanation:

solve like a multi step

7 0
3 years ago
Translate this sentence into an equation. 59 is the sum of 11 and Mai’s score
trapecia [35]

Answer:

11 + Mai's Score = 59

Step-by-step explanation:

You need to add 11 and Mai's score together to get 59, so with the values given we can make the equation 11 + Mai's Score = 59.

*depending on the question, Mai's score may need to be said as a letter variable, so:

If m = mai's score,

11 + m = 59

I hope this helped! :)

3 0
3 years ago
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For two events and , the probability that occurs is 0.8, the probability that occurs is 0.4, and the probability that both occur
sergey [27]

Answer:

P(B|A)=0.25  , P(A|B) =0.5

Step-by-step explanation:

The question provides the following data:

P(A)= 0.8

P(B)= 0.4

P(A∩B) = 0.2

Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.

To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:

P(B|A) = P(A∩B)/P(A)

      = (0.2) / (0.8)  

P(B|A)=0.25

To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:

P(A|B) = P(A∩B)/P(B)

          = (0.2)/(0.4)

P(A|B) =0.5

7 0
3 years ago
A past study claims that adults in America spend an average of 17 hours a week on leisure activities. A researcher wanted to tes
8090 [49]

Answer:

The claim is false.

Step-by-step explanation:

Given the data :

13 24 21 37 15 25 18 22 40 32

The sample mean and standard deviation can ben calculated for the given sample.

Using calculator :

Sample mean, xbar = 24.7

Sample standard deviation, s = 9.04

Sample size, n = 10

The hypothesis :

H0 : μ = 17

H1 : μ ≠ 17

The test statistic :

(xbar - μ) ÷ (s/√(n))

(24.7 - 17) ÷ (9.04/√(10))

7.7 / 2.8586990

Test statistic = 2.694

We can obtain the Pvalue, at α = 0.05 ; df = n-1 = 9

Pvalue = 0.0246

Since Pvalue < α ; we reject the null ; Hence, there is significant evidence to conclude that an adult American does not spend average of 17 hours in leisure

5 0
2 years ago
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