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Darina [25.2K]
3 years ago
10

Which steps can be used to verify that tan(w + Pi) = tan(w)? Rewrite tan(w + Pi) as tan(w) + tan(Pi). Then simplify the expressi

on using tan(Pi) = 1. Rewrite tan(w + Pi) as tan(w) + tan(Pi). Then simplify the expression using tan(Pi) = 0. Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 1. Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0.
Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0

Step-by-step explanation:

According to tangent sub identity

Tan(A+B) = TanA+TanB/1-tanAtanB

Applying this in question

Tan(w+Pi) = tan(w)+tan(pi)/1-tan(w)tan(pi)

According to trig identity, tan(pi) = 0

Substitute

Tan(w+Pi) = tan(w)+0/1-tan(w)(0)

Tan(w+Pi) = tan(w)/1

Tan(w+Pi) = tan(w) (proved!)

Hence the correct option is

Rewrite tan(w + Pi) using the tangent sum identity. Then simplify the resulting expression using tan(Pi) = 0

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If CP=Rs. 1200 and loss =10%, find loss amount.​
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Anastasy [175]

Answer:

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Step-by-step explanation:

You know they have the same y intercept, so first you should find the y intercept of the givern equation.

<em>x+2y = 10   </em>

<em>2y = -x + 10        [subtract x]</em>

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3 years ago
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Answer:

Step-by-step explanation:

given is a function as

y=\frac{27}{x^3}

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Area = \int\limits^t_1 {\frac{27}{x^3} } \, dx \\=\frac{-27}{2x^2} \\= \frac{-27}{2t^2}-\frac{-27}{2}\\=\frac{27}{2}(1-\frac{1}{t^2} )

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c) t=10000

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