The domain of f/g
consists of numbers x for which g(x) cannot equal 0 that are in the domains of
both f and g.
Let’s take this equation as an example:
If f(x) = 3x - 5 and g(x)
= square root of x-5, what is the domain of (f/g)x.
For x to be in the domain of (f/g)(x), it must be
in the domain of f and in the domain of g since (f/g)(x) = f(x)/g(x). We also
need to ensure that g(x) is not zero since f(x) is divided by g(x). Therefore,
there are 3 conditions.
x must be in the domain of f:
f(x) = 3x -5 are in the domain of x and all real numbers x.
x must be in the domain of g:
g(x) = √(x - 5) so x - 5 ≥ 0 so x ≥ 5.
g(x) can not be 0: g(x)
= √(x - 5) and √(x - 5) = 0 gives x = 5 so x ≠ 5.
Hence to x x ≥ 5 and x ≠ 5
so the domain of (f/g)(x) is all x satisfying x > 5.
Thus, satisfying <span>satisfy all
three conditions, x x ≥ 5 and x ≠ 5 so the domain of (f/g)(x) is all x
satisfying x > 5.</span>
Answer: I need more to solve this
Step-by-step explanation:
Answer:
depends on the options
Step-by-step explanation:
a parallel line would be y = 1/2x + b, where b is any number
You subtract 5 from both sides to get n=8
Answer:
∴ Constant of Proportionality is 32
Step-by-step explanation:
Here Given;
(equation-1)
(equation-2) (divide with 'g' on both side)
We know,
The Constant of Proportionality equation is given;
(equation-3)
Where 'k' is known as Constant of Proportionality.
Comparing equation-1 and equation-3;
and 
Now equation-2 become;
Plug and in above equation;
(equation-4)
By comparing equation-2 and equation-4;
So Constant of Proportionality is 32
