-12x-20-40plus 16x
-4x plus -60
Answer:
0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
Step-by-step explanation:
Given the data in the question;
sample size n = 28
slope of the least squares regression line of y on x or sample estimate = 0.0623
standard error = 0.0224
95% confidence interval
level of significance ∝ = 1 - 95% = 1 - 0.95 = 0.05
degree of freedom df = n - 2 = 28 - 2 = 26
∴ the equation will be;
⇒ sample estimate ± ( t-test) ( standard error )
⇒ sample estimate ± ( 
) ( standard error )
⇒ sample estimate ± ( 
) ( standard error )
⇒ sample estimate ± ( 
) ( standard error )
{ from t table; ( ) = 2.055529 = 2.056
so we substitute
⇒ 0.0623 ± ( 2.056 )( 0.0224 )
Therefore, 0.0623 ± ( 2.056 )( 0.0224 ) can be used to compute a 95% confidence interval for the slope of the population regression line of y on x
Answer:
Each of them spent $9.35 on meal.
Step-by-step explanation:
Jacob and his three friends ordered an individual pizza and a drink for $6.19.
Total cost of pizza and drink = 6.19 × 4
= $24.76
They also ordered bread sticks for $4.25
Tax on the bill was = $2.39
Tip amount was = $1.50×4 = $6.0
So the total billed amount will be = 24.76 + 4.25 + 2.39 + 6
= $37.4
Since there were four persons including Jacob.
Therefore, each person spend on meal = 
= $9.35
Answer:
Multiply numerator and denominator with same number to gwt the answers . There are infinitely many numbers
3/10 × 2/2 = 6/20
3/10 × 5/5 = 15/50
3/10 × 10/10 = 30/100
And so on
<span>An algebraic expression is an expression constructed from a number of constants and variables utilizing algebraic operations. These algebraic operations are addition, subtraction, multiplication, division, and exponentiation. A constant is constant, so its value is unchanged. A variable changes based on the value provided. In the provided example, 2x-1, there are two constants, "2" and "1", and one variable "x." The algebraic operations utilized are multiplication and subtraction. In order to evaluate the value of the algebraic expression, the given value for the variable must be substituted for the variable x, and then the algebraic operations executed to obtain the answer.
For instance, if you were told that the value of x in this case was 2, then you would substitute the value 2 for x and perform the described operations. Remember to follow the order of operations when evaluating an algebraic expression!
2x-1 for x=2
2(2) - 1
4 - 1
3 is the answer.
Remember, even though the multiplication operation is not explicitly stated, it is implied that a constant attached to a variable (termed a coefficient) is multiplied with the value of the variable.</span>
