The length of the midsegment of an isosceles trapezoid is the sum of the two bases, divided by 2. So this means -
(base 1+base2) / 2
(12+20) / 2
32/2
Length of midsegment = 16
Answer:
the answer is h=0.5m+2 I think
Answer:
3/5
Step-by-step explanation:
sin theta=opposite/hypotenuse
4/5=opposite/hypotenuse
therefore opposite=4 and hypotenuse=5
for adjacent
using pythagoras theorem
a^2+b^2=c^2
opposite^2 + adjacent^2 =hypotenuse^2
4^2 + adjacent^2 =5^2
16 + adjacent^2 =25
adjacent^2 =25-16
adjacent =
adjacent=3
cos theta=adjacent/hypotenuse
=3/5
therefore the value of cos theta is 3/5
Answer:
3 1/11
Step-by-step explanation:
8 1/2 x 4/11
Change to an improper fraction
(2*8+1)/2 * 4/11
17/2 * 4/11
68 /22
Divide the top and bottom by 2
34/11
Change back to a mixed number
11 goes into 34 3 times with 1 left over
3 1/11
Answer:
work it out it is so easy
Step-by-step explanation: