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SashulF [63]
3 years ago
11

Bill rented a truck for one day.There was a base fee of $15.95,and there was a additional charge of 92 cents for each mile drive

n.Bill had to pay $265.27 when he returned the truck.For how many miles did he drive the truck
Mathematics
1 answer:
denpristay [2]3 years ago
6 0

Answer:

271 miles

Step-by-step explanation:

15.95+0.92 x=265.27

0.92 x=265.27-15.95

.92 x=249.32

x=24932/92=271

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a garage floor measures 150 feet by 120 feet. a scale drawing of the floor on grid paper uses a scale of one unit : 15 feet. wha
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1 unit = 15 feet

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120 feet / 1 unit = 120 / 15 = 8 units

The dimensions of the drawing equates :

10 units by 8 units .

hope this helps!

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The difference between Lana's and her younger sister Lee's ages is 2. If Lee is 17 years old, how old is Lana? Let x represent L
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Answer:

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2 years ago
Solve the equation.<br><br> <img src="https://tex.z-dn.net/?f=w%2F3%20%3D%20-9" id="TexFormula1" title="w/3 = -9" alt="w/3 = -9"
kvasek [131]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
Brewed decaffeinated coffee contains some caffeine. We want to estimate the amount of caffeine in 8 ounce cups of decaf coffee a
rusak2 [61]

Answer:

We would have to take a sample of 62 to achieve this result.

Step-by-step explanation:

Confidence level of 95%.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Assume that the standard deviation in the amount of caffeine in 8 ounces of decaf coffee is known to be 2 mg.

This means that \sigma = 2

If we wanted to estimate the true mean amount of caffeine in 8 ounce cups of decaf coffee to within /- 0.5 mg, how large a sample would we have to take to achieve this result?

We would need a sample of n.

n is found when M = 0.5. So

M = z\frac{\sigma}{\sqrt{n}}

0.5 = 1.96\frac{2}{\sqrt{n}}

0.5\sqrt{n} = 2*1.96

Dividing both sides by 0.5

\sqrt{n} = 4*1.96

(\sqrt{n})^2 = (4*1.96)^2

n = 61.5

Rounding up

We would have to take a sample of 62 to achieve this result.

8 0
3 years ago
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