Answer:
the answer and problem shown above
Answer:
The P-value for this test is P=0.2415.
Step-by-step explanation:
We have to perform an hypothesis testing on the mean of alla account balances.
The claim is that the mean of all account balances is significantly greater than $1,150.
Then, the null and alternative hypothesis are:

The sample size is n=20, with a sample mean is 110 and standard deviation is 125.
We can calculate the t-statistic as:

The degrees of freedom fot this test are:

For this one-tailed test and 19 degrees of freedom, the P-value is:

f(x) -g(x) = -3x-5 -(4x-2)
distribute
-3x-5 -4x+2
combine like terms
-7x-3
Answer:
-7x-3
divide 486 by 9 = 54
it would take about 54 minutes