Answer:
The minimum number of fish each must have caught is 90 fishes
Step-by-step explanation:
The number of fishes Tisha's net can hold = 15
The number of fishes Dana's net can hold = 18
Let the total number of fishes both Tisha and Dana caught = X
15 × A = 18 × B = X
Therefore, X is the lowest common multiple (LCM) of 15 and 18 given as follows;
15 = 3 × 5
18 = 3 × 6
Therefore, the LCM of 18 and 5 = 3 × 5 × 6 = 90
Which gives, the minimum number of fish each must have caught = 90 fishes.
Answer:
$9.68
Step-by-step explanation:
Divide 58.08 / 6 and you get 9.68, this is 1st grade math (:
Answer:
Last choice.
Step-by-step explanation:
To find the option that is equivalent to this equation, we can begin by narrowing down our options. The slope contains a negative number, meaning the second point must have a lower y value than the first.
Using this criteria, we can eliminate the first and the third answer. Now, we can test the second and fourth answer.
We can test using the slope formula and plugging in values. When the slope formula: 
We get a slope of -5 for both of these equations. Let's plug in the point values to check whether they work:
Choice 2:
-24 = -5(4) + 4
-24 = -20 + 4
-24 ≠ -16
Choice 4:
-16 = -5(4) + 4
-16 = -20 + 4
-16 = -16
Therefore, choice 4 is correct!
Answer:
part A:d=5.4-3.1
Part B:t=4.9+3.1
Part C:If ted walks 5.4 kilometers,then david walks 2.3 kilometers,If david walks 4.9 kilometers,then ted walks 8 kilometers.
To find the answer to -10x=-210 you must divide -210 by -10
-210/-10= 21
Therefore x=21
So the proper equation is -10(21)=-210