Answer:
The minimum score required for the scholarship is 644.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the minimum score required for the scholarship?
Top 8%, which means that the minimum score is the 100-8 = 92th percentile, which is X when Z has a pvalue of 0.92. So it is X when Z = 1.405.
The minimum score required for the scholarship is 644.
Answer:
n
=
−
14
Step-by-step explanation:
-3(n+5)=27
-(3n+3·5)=27
-(3n+15)=27
Please mark me brainliset if this helped (I need it)
Answer:
15
Step-by-step explanation:
0 + 1 = 1
1 + 2 = 3
3 + 3 = 6
6 + 4 = 10
10 + 5 = 15
Answer:
I think its 22..
Step-by-step explanation:
Add 7 and 6
the subtract 35 by what you got from adding 7 and 6 (13).
Answer:
The mass of 150 books = 41.7kg
The number of books that have mass 20kg = 72 books
Step-by-step explanation:
(I) Number of identical books = 108
Mass of books = 30 kg
Mass of 150 books = ?
Let the mass of 150 books = x kg
To find the mass of 150 books we will use ratio and proportion:
108 books: 30kg = 150 books: x kg
You can also write it like this because ratio can be written in division:
108/30 = 150/x
By cross multiplication:
108x = 150*30
108 x= 4500
Divide both sides by 108
108 x/108 = 4500/108
x= 41.7
Thus the mass of 150 books = 41.7kg
( ii ) The number of books that have a mass of 20 kg = ?
Let assume that the number of books of mass 20 kg = y books
We will again use ratio and proportion method.
108 books: 30kg = y: 20kg
We can write it as:
108/30 = y/20
By cross multiplication:
108 *20 = 30y
2160= 30y
Divide both the terms by 30
2160/30 = 30y/30
72 = y
Therefore the number of books that have mass 20kg = 72 books ....
