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zzz [600]
4 years ago
5

A farmer measures the distance around a rectangular field. The length of each long side of the rectangle is found to be 20.33 m,

and the length of each short side is found to be 16.9 m. What is the total distance around the field?1. Two significant figures (130 m)2. Five significant figures (134.56 m)3. Whole number (135 m)4. Tenths (134.6 m)5. Three significant figures (135 m)6. Hundredths (134.56 m)7. Four significant figures (134.6 m)8. None of these
Mathematics
1 answer:
Tasya [4]4 years ago
3 0
<h2>Answer:</h2>

<em><u>Distance of the farmer's rectangular field around the field = 74.46 m</u></em>

<h2>Step-by-step explanation:</h2>

In the given question,

Length of the rectangular field, L = 20.33 m

Width of the rectangular field, W = 16.9 m

Now,

The area of rectangular field is given by,

The total distance around the rectangular field is,

Distance = Perimeter of the the rectangle.

Perimeter of rectangle = 2(Length + Width)

Perimeter = 2(20.33 + 16.9)

Perimeter = 2(37.23)

Perimeter = 74.46 m

So,

<em><u>Distance of the farmer's rectangular field around the field is = 74.46 m</u></em>

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Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=4, u′(0)=7, v(0)=2 and v′(0)=1. Find the values
Leona [35]

Answer with Step-by-step explanation:

We are given that u and v are functions of x and both are differentiable at x=0

u(0)=4,u'(0)=7,v(0)=2,v'(0)=1

a.We have to find the values of \frac{d(uv)}{dx}

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Using this formula

Then , we get

[\frac{d(uv)}{dx}]_{x=0}=u'(0)v(0)+u(0)v'(0)=7(2)+4(1)=14+4=18

[\frac{d(uv)}{dx}]_{x=0}=18

b.\frac{d(u/v)}{dx}=\frac{u'v-uv'}{v^2}

[\frac{d(u/v)}{dx}]_{x=0}=\frac{u'(0)v(0)-u(0)v'(0)}{v^2(0)}=\frac{7(2)-4(1)}{2^2}=\frac{14-4}{4}=\frac{10}{4}=\frac{5}{2}

[\frac{d(u/v)}{dx}]_{x=0}=\frac{5}{2}

c.

[\frac{d(v/u)}{dx}]_{x=0}=\frac{v'(0)u(0)-v(0)u'(0)}{u^2(0)}=\frac{1(4)-7(2)}{4^2}

[\frac{d(v/u)}{dx}]_{x=0}=\frac{-10}{16}=\frac{-5}{8}

d.\frac{d(-6v-9u)}{dx}=-6v'-9u'

[\frac{d(-6v-9u)}{dx}]_{x=0}=-6v'(0)-9u'(0)=-6(1)-9(7)=-6-63=-69

[\frac{d(-6v-9u)}{dx}]_{x=0}=-69

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