It’s definitely not B so don’t chose that one because it’s not right
Answer:
Prove: ΔPYJ ≅ ΔPXK
Step-by-step explanation:
Overlapping triangles are said to be triangles that share at least part of a side or an angle.
To prove ΔPYJ is congruent to ΔPXK
First we would draw the diagram obtained from the given information.
Find attached the diagram.
Given:
JP = KP
PX = PY
From the diagram, ΔPYJ and ΔPXK share the line KJ (part of the side of each of the triangle)
KJ ≅ KJ (A reflexive property - the segment is congruent to itself)
In ∆PYJ
JP = KP + KJ
In ∆PXK
KP = JP + KJ
Since JP = KP
KP + KJ = JP + KJ
PJ ≅ PK
The overlapping section makes a smaller triangle KXJ
∠K = ∠J (opposite angles of congruent sides are equal)
In ∆PYJ: PY + YJ + PJ (sum of angles in a triangle)
In ∆PXK: PX + XK + PK (sum of angles in a triangle)
If ΔPYJ ≅ ΔPXK
PY + YJ + PJ = PX + XK + PK
XK ≅ YJ
Therefore, ΔPYJ ≅ ΔPXK
Answer:
B but am not sure tho it's probably A
Assuming that each marble can be picked with equal probability, we notice that there is a total of

marbles, of which 2 are red.
So, the probability of picking a red marble is

In fact, as in any other case of (finite) equidistribution, we used the formula

Answer:
(h,k) = (32,-4)
r = 32
Step-by-step explanation:
The general equation for a circle is given by:
(1)
where (h,k) is the center of the circle and r is the radius.
You have the following equation:
(2)
You first need to complete squares in order to obtain an equation of the form (1). Thus, you have that the second term must be in a perfect square trinomial:
2b = 64
b = 32
Then, you have to sum 32^2 and also subtract the same number in the expression (2):

you compare the last result with expression (1) and obtain that the raiuds of the circle is r = 32
Furthermore, the center of the circle is (h,k) = (32,-4)