A parallelogram has vertices E(-8,3), F(2,-2), G(-1,3), and H(-5,-2). What are the coordinates of the midpoint of each diagonal?

Price-club sells a 12-ounce box of crackers for $2.59 and Shop Mart sells 1-1/2 pound box of crackers for $4.68. What is the uni

katen-ka-za [31]

Unit price would be the price per ounce.

Divide the total cost by the number of ounces:

Price Club : 2.59 / 12 = $0.216 per ounce

Shop Mart: 1-1/2 pounds = 1.5 x 16 = 24 ounces.

4.68 / 24 = $0.195 per ounce.

7 0

3 years ago

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Help! Which estimate is closest to the actual value of ( 2.99548 ) ⋅ ( 1.8342 )?

nordsb [41]

Answer:

Step-by-step explanation:

2.99548 * 1.8342

the first number rounds to 3.....the second number rounds to 2.....3 * 2 = 6...but it will be a little short of 6 because of the 1.8.....so I am going with 5.5

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jada ran 7.1 miles.....noah ran 5.123 miles

so jada ran (7.1 - 5.123) = 1.977 miles farther then noah

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greater then 3...

1.67 + 1.4 and 4.5 - 1.47

8 0

3 years ago

It has long been reported that human body temperature follows a normal distribution with a mean of 98.6 degrees Fahrenheit. Ther

Kay [80]

Solution :

The normal body temperature of any human body is considered to be 98.6 $^\circ \ F$ . But there is a constant debate about the body temperature of a long held standard to the body temperature.

It is given that :

Null hypothesis and alternate hypothesis :

$H_0 : \mu = 98.6$

And $H_A : \mu > 98.6$

n is given as = 180

Test statistics = 3.64

Prove = 0.018 < α = 0.05 (let reject null hypothesis for α = 0.05 )

Therefore, their results are statistically significant and the result is unlikely due to chance alone.

7 0

3 years ago

20 POINTS!!!

notka56 [123]

$\dfrac{2}{\sqrt3\cos x+\sin x}=\sec\left(\dfrac{\pi}{6}-x\right)\\\\\dfrac{2}{\sqrt3\cos x+\sin x}=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}\ \ \ \ \ (*)\\----------------\\\\\cos\left(\dfrac{\pi}{6}-x\right)\ \ \ \ |\text{use}\ \cos(x-y)=\cos x\cos y+\sin x\sin y\\\\=\cos\dfrac{\pi}{6}\cos x+\sin\dfrac{\pi}{6}\sin x=\dfrac{\sqrt3}{2}\cos x+\dfrac{1}{2}\sin x=\dfrac{\sqrt3\cos x+\sin x}{2}\\------------------------------$

$(*)\\R_s=\sec\left(\dfrac{\pi}{6}-x\right)=\dfrac{1}{\cos\left(\dfrac{\pi}{6}-x\right)}=\dfrac{1}{\dfrac{\sqrt3\cos x+\sin x}{2}}\\\\=\dfrac{2}{\sqrt3\cos x+\sin x}=L_s$

6 0

3 years ago

Read 2 more answers

A coffee company wants to make sure that their coffee is being served at the right temperature. If it is too hot, the customers

Cerrena [4.2K]

Answer:

Null hypothesis: $\mu = 65$

Alternative hypothesis: $\mu \neq 65$

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

For this case the value of $\mu$ represent the parameter associated to the population (True average of cofee temperature)

Step-by-step explanation:

Data given and notation

$\bar X=70.2$ represent the mean height for the sample

$s$ represent the sample standard deviation for the sample

$n=20$ sample size

$\mu_o =765$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the true mean i equal to 70.2, the system of hypothesis would be:

Null hypothesis: $\mu = 65$

Alternative hypothesis: $\mu \neq 65$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

For this case the value of $\mu$ represent the parameter associated to the population (True average of cofee temperature)

3 0

3 years ago