All categories

3 years ago

A parallelogram has vertices E(-8,3), F(2,-2), G(-1,3), and H(-5,-2). What are the coordinates of the midpoint of each diagonal?

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

6 0

Hello,
Please, see the attached file.
Thanks.

You might be interested in

-b+- square root of (b*b) -4ac/2a

Jet001 [13]

This is the quadratic formula.

7 0

3 years ago

Nan rode the roller coaster 8 times, which was twice as many times as she rode the F erris wheel

lyudmila [28]

So she rode the Ferris Wheel 4 times. 8/2= 4

8 0

3 years ago

I need help with problems 20,22,24,26 and 28

Nostrana [21]

Convert milliliters to feet and then multiply 1 1/4 by 3 do the same but convert to the problems it says

5 0

3 years ago

PLZ HELP FAST!!!! WILLL GIVEE BRANILIESTTTTT!!Which of the following best describes the pyramid represented by this net? square

DedPeter [7]

Answer:

How can send/put/mark someone braniliest

7 0

3 years ago

Gravel is being dumped from a conveyor belt at a rate of 20 ft3 /min and its coarseness is such that it forms a pile in the shap

pantera1 [17]

Answer:

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

Step-by-step explanation:

Given that :

Gravel is being dumped from a conveyor belt at a rate of 20 ft³ /min

i.e $\dfrac{dV}{dt}= 20 \ ft^3/min$

we know that radius r is always twice the diameter d

i.e d = 2r

Given that :

the shape of a cone whose base diameter and height are always equal.

then d = h = 2r

h = 2r

r = h/2

The volume of a cone can be given by the formula:

$V = \dfrac{\pi r^2 h}{3}$

$V = \dfrac{\pi (h/2)^2 h}{3}$

$V = \dfrac{1}{12} \pi h^3$

$V = \dfrac{ \pi h^3}{12}$

Taking the differentiation of volume V with respect to time t; we have:

$\dfrac{dV}{dt }= (\dfrac{d}{dh}(\dfrac{\pi h^3}{12})) \times \dfrac{dh}{dt}$

$\dfrac{dV}{dt }= (\dfrac{\pi h^2}{4} ) \times \dfrac{dh}{dt}$

we know that:

$\dfrac{dV}{dt}= 20 \ ft^3/min$

So;we have:

$20= (\dfrac{\pi (15)^2}{4} ) \times \dfrac{dh}{dt}$

$20= 56.25 \pi \times \dfrac{dh}{dt}$

$\mathbf{\dfrac{dh}{dt}= \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

The height of the pile is increasing at the rate of $\mathbf{ \dfrac{20}{56.25 \pi} \ \ \ \ \ ft/min}$

8 0

3 years ago