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3 years ago

Whats the equation of a line parallel to y=-1/2x+6 that passes through (-4,1)

Mathematics

1 answer:

gtnhenbr [62]3 years ago

5 0

Answer:

y=-1/2x-6

Step-by-step explanation:

Find the slope of the original line and use the slope-intercept form

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The mean height of an adult giraffe is 18 feet. Suppose that the distribution is normally distributed with standard deviation 0.

Klio2033 [76]

Answer:

1. the probability that giraffe will be shorter than 17 feet tall is equal to 0.1056

2. the probability that a randomly selected giraffe will be between 16 and 19 feet tall is equal to 0.8882

3. the the 90th percentile for the height of giraffes is 19.024

Step-by-step explanation:

To calculate the probability that a giraffe will be shorter than 17 feet tall, we need to standardize 17 feet as:

$z=\frac{x-m}{s}$

Where x is the height of the adult giraffe, m is the mean and s is the standard deviation, so 17 feet is equivalent to:

$z=\frac{17-18}{0.8}=-1.25$

Now, the probability that giraffe will be shorter than 17 feet tall is equal to P(z<-1.25). Then, using the standard normal distribution table, we get that:

$P(z$

At the same way, 16 and 19 feet tall are equivalent to:

$z=\frac{16-18}{0.8}=-2.5\\z=\frac{19-18}{0.8}=1.25$

So, the probability that a randomly selected giraffe will be between 16 and 19 feet tall is equal to:

$P(-2.5$

Finally, to find the the 90th percentile for the height of giraffes, we need to find the value z that satisfy:

$P(Z$

Now, using the standard normal distribution table we get that z is equal to 1.28. Therefore, the height x of the giraffes that is equivalent to 1.28 is:

$z=\frac{x-m}{s} \\1.28=\frac{x-18}{0.8} \\x=(1.28*0.8)+18\\x=19.024$

it means that the the 90th percentile for the height of giraffes is 19.024

4 0

3 years ago

Please answer quickly, (1 question, 30 pts) thanks!

kaheart [24]

Step-by-step explanation:

once the level of medicine reaches a value, where 30% are 23mL (so, whatever is lost, is immediately replaced again), that is then the long run value for the amount of the drug in the patient's body.

so,

30% = 23 mL

1% = 30%/30 = 23/30 = 0.766666666...

100% = 1%×100 = 0.766666666... × 100 = 76.666666...

so, once the level reaches 76.666666... mL in the body, it will remain constant, as the daily filtered out 30% are 23 mL, and the daily add-on is also 23 mL.

so, the answer is

76.667 mL

5 0

2 years ago

For geometry:(<br><br> will give brainist to the correct answer!!!

Pani-rosa [81]

Answer:

y = ⅔x - 5

Step-by-step explanation:

The line that is parallel to 2x - 3y = 24, would have the same slope as the line, 2x - 3y = 24.

Rewrite;

2x - 3y = 24

-3y = -2x + 24

Divide both sides by -3

y = ⅔x - 8

Thus, the slope of 2x - 3y = 24 is ⅔.

Therefore the line that is parallel to 2x - 3y = 24, will have a slope (m) of ⅔.

Using point-slope form, we can generate an equation that passes through (-3, -7) and is parallel to 2x - 3y = 24.

Thus, substitute (a, b) = (-3, -7) and m = ⅔ into y - b = m(x - a)

Therefore:

y - (-7) = ⅔(x - (-3))

y + 7 = ⅔(x + 3)

Rewrite in slope-intercept form.

Multiply both sides by 3

3(y + 7) = 2(x + 3)

3y + 21 = 2x + 6

3y = 2x + 6 - 21

3y = 2x - 15

Divide both sides by 3

y = ⅔x - 5

7 0

3 years ago

SOLVE. integration of (1-v) /(1+v^2)

Marta_Voda [28]

I think you have to first separate the integral:1/(1+v^2) + v/(1+v^2),
so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:

y= 1+v^2
so
dy= 2v
and
v= dy/2and then you substitute:v/(1+v^2) = (1/2)(dy/y)
and the integral is
(1/2) (In y)finally you plug in the initial variables:

(1/2)(In [1+v^2])

so the total integral is:

ArcTan (y) + (1/2)(In [1+v^2])

6 0

3 years ago

Read 2 more answers

If the order of three loci is A B C, and the map distance between A and B is 15 m.u., and the map distance between B and C is 20

zysi [14]

Answer:

Therefore, we conclute that the map distance between A and C is 35 m.u..

Step-by-step explanation:

We know that the order of three loci is A B C, and the map distance between A and B is 15 m.u., and the map distance between B and C is 20 m.u. We calculate the map distance between A and C.

Therefore, we get

$AC=AB+BC\\\\AC=15+20\\\\AC=35\\$

Therefore, we conclute that the map distance between A and C is 35 m.u..

4 0

3 years ago