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Ksju [112]
3 years ago
12

Last night, the temperature fell from 0°F to Negative 13 and one-fifth°F in4 and two-fifths hours. Alan calculated the average t

emperature change per hour.
Negative 13 and one-fifth divided by 4 and two-fifths = Negative StartFraction 66 over 5 EndFraction divided by StartFraction 22 over 5 EndFraction = Negative StartFraction 66 over 5 EndFraction (StartFraction 22 over 5 EndFraction) = Negative StartFraction 1,452 over 25 EndFraction
Alan solved the problem, but when he checked the answer by estimating, it didn’t seem right. What error did he make?
Alan converted the mixed number to the wrong improper fraction.
He did not use the correct reciprocal fraction.
He did not change the division problem to multiplication.
He added the numerators and denominators instead of multiplying.
Mathematics
2 answers:
Sever21 [200]3 years ago
7 0

Answer:

the real answer is b

Step-by-step explanation:

hope this helps:^

USPshnik [31]3 years ago
5 0
Negative 3.14
Times that by Pi which is 3.14 and then multiply by the base number and you will get the correct answer
You might be interested in
Four friends go to an amusement arcade.
galben [10]

<u><em>Answer:</em></u>

<u>The rule is: </u>

T(x) = 8x + 20

<em><u>Explanation:</u></em>

<u>We are given that:</u>

<u>The rule for the amount that one friend pays is:</u>

C(x) = 2x + 5

<u>Now, we know that:</u>

Each of the four friends will pay the entry fee which is $5 per person

The 4 friends will play the same number of games represented by x

<u>This means that:</u>

We can simply get the rule for the total amount to be paid by the four friends (T(x)) by multiplying the amount paid by each friend by 4

<u>This means that:</u>

T(x) = 4 * C(x)

T(x) = 4(2x + 5)

T(x) = 8x + 20

Hope this helps :)

4 0
3 years ago
A cylinder has a volume of 2167 cubic feet and a height of 18 feet What is the area of the base?
natita [175]

Answer:

120.39ft²

Step-by-step explanation:

Hopefully that helps :)

6 0
3 years ago
The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea level, then the pres
seraphim [82]

Answer:

373.8mmHg

Step-by-step explanation:

a =height (in km) above sea level,

the pressure P(a) (in mmHg) is approximated given as

P(a) = 760e–0.13a .

To determine the atmospheric pressure at 5.458 km, then we will input into the equation

P(5.458km) = 760e–0.13a .

= 760e^(-0.13×5.458)

=760e^-(0.70954)

= 760×0.4919

=373.8mmHg

Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg

3 0
3 years ago
Please anyone can help
Anestetic [448]
The answer to the question

5 0
3 years ago
Read 2 more answers
Solve for x. <br><br> Brainlest for anyone who helps!! <br><br> thanks you
gavmur [86]
<h3>Answer:  C) 0</h3>

================================================

Explanation:

If points F and E are the midpoints of segment VU and segment ST respectively, then segment FE is the midsegment of the trapezoid. The midsegment is parallel to the bases, and the midsegment's length is found by adding up the bases VS and UT, then dividing by 2.

(VS + UT)/2 = FE

(29 + x+17)/2 = 23 ... plug in given info; isolate x

(x+46)/2 = 23

x+46 = 23*2 ... multiply both sides by 2

x+46 = 46

x = 46-46 ... subtract 46 from both sides

<h3>x = 0</h3>
6 0
3 years ago
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