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arsen [322]
2 years ago
5

What is 100 divided by 11.99?

Mathematics
2 answers:
Svetach [21]2 years ago
8 0

Answer:

8.4033613445378151260504201680672

Step-by-step explanation:

Use a calculator :)

Lena [83]2 years ago
4 0

Answer:

\frac{1000}{1199} = 8.34028

Step-by-step explanation:

multiply 100 by 100 = 1000

and multiply 11.99 by 100 = 1199

divide them you get 10000/1199

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As part of the Pew Internet and American Life Project, researchers conducted two surveys in late 2009. The first survey asked a
REY [17]

Answer:

The 95% confidence interval for the difference between the proportion of all U.S. teens and adults who use social networking sites is (0.223, 0.297). This means that we are 95% sure that the true difference of the proportion is in this interval, between 0.223 and 0.297.

Step-by-step explanation:

Before building the confidence interval we need to understand the central limit theorem and the subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Sample of 800 teens. 73% said that they use social networking sites.

This means that:

p_T = 0.73, s_T = \sqrt{\frac{0.73*0.27}{800}} = 0.0157

Sample of 2253 adults. 47% said that they use social networking sites.

This means that:

p_A = 0.47,s_A = \sqrt{\frac{0.47*0.53}{2253}} = 0.0105

Distribution of the difference:

p = p_T - p_A = 0.73 - 0.47 = 0.26

s = \sqrt{s_T^2+s_A^2} = \sqrt{0.0157^2+0.0105^2} = 0.019

Confidence interval:

Is given by:

p \pm zs

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Lower bound:

p - 1.96s = 0.26 - 1.96*0.019 = 0.223

Upper bound:

p + 1.96s = 0.26 + 1.96*0.019 = 0.297

The 95% confidence interval for the difference between the proportion of all U.S. teens and adults who use social networking sites is (0.223, 0.297). This means that we are 95% sure that the true difference of the proportion is in this interval, between 0.223 and 0.297.

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2 years ago
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Answer:

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3x + 4y = 24<br> 6x + 8y = 24 using process of elimination
Lelechka [254]

Answer:

false

Step-by-step explanation:

3x+4y=24 multiplied by 2 equals: 6x+8y=48

if you subtract 6x+8y=24 from 6x+8y=48, you get 0=24, which is not true. Therefore the statement is false.

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Two numbers has the same greatest common factor as 27 and 36 have. Which two numbers could it be? 9 and 12, 12 and 18, 18 and 45
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9 is the GCF of 27 and 36, and also of 18 and 45.
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