I hope this helps you
f (x)=3 square root of x
Answer:
12x +8y +1 = 0
Step-by-step explanation:
You can write the equation by swapping the x- and y-coefficients and negating one of them. Then compute the constant that makes the line go through the given point. You can do that like this:
3(x-(-3/4)) +2(y -1) = 0
3x +9/4 +2y -2 = 0 . . . . eliminate parentheses
3x +2y +1/4 = 0 . . . . . . . simplify
To eliminate the fraction, multiply by 4:
12x +8y +1 = 0
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<em>Comment on the equation</em>
The line ax+by=0 passes through the origin. Replacing x and y with x-h and y-k, respectively, makes the line pass through the point (h, k). That's what we did above to make the line pass through the given point.
The business of swapping coefficients and negating one causes the slope of the new line to be the negative reciprocal of the slope of the original line. That is what makes the new line perpendicular to the original.
Answer:
Trial- 2 shows the conservation of momentum in a closed system.
Step-by-step explanation:
Given: Mass of balls are 
Conservation of momentum in a closed system occurs when momentum before collision is equal to momentum after collision.
- Let initial velocity of ball

- Initial velocity of ball

- Final velocity of ball

- Final velocity of ball

- Momentum before collision

- Momentum after collision

Now, According to conservation of momentum.
Momentum before collision = Momentum after collision

We will plug each trial to this equation.
Trial 1

Trial 2

Trial 3

Trial 4

We can see only Trial 2 satisfies the princple of conservation of momentum. That is momentum before collison should equal to momentum after collision.
Answer:
Do you want the derivative?!
Answer:
The equation of the line segment between points A and X is
![sA + (1-s)X, s\in[0,1]](https://tex.z-dn.net/?f=sA%20%2B%20%281-s%29X%2C%20s%5Cin%5B0%2C1%5D)
Then we need that the point C satisfy:
.
This implies that

We replace the value of s in the equation we get from the second component

Then the point
lies on the line through A and X.