First youll want to add 18 and 29. which gives you 43. then you’ll want to find out how much is 29 people percentage wise. so you’ll do 29/43 which gives you 67.44% if it’s answer choices. you round it to the most whole number if they don’t use decimals.
20 = 2 x 2 x 5
15 = 3 x 5
common divisor (CD) of 20 and 15 is 5 so n should be 5 and each group has 4 boys and 3 girls.
If there are more than one CD, then there are more than one answer.
If they ask for the largest number of groups, greatest common divisor (GCD) will be the answer.
Answer:
(2)y²
Step-by-step explanation:
2 x y²
Answer: A. 
B. A'(5) = 1.76 cm/s
Step-by-step explanation: <u>Rate</u> <u>of</u> <u>change</u> measures the slope of a curve at a certain instant, therefore, rate is the derivative.
A. Area of a circle is given by

So to find the rate of the area:


Using 

Then
![\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%3D2.%5Cpi.r.%5B%5Cfrac%7B726%7D%7B%28t%2B11%29%5E%7B3%7D%7D%5D)
![\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdt%7D%3D2.%5Cpi.%5B3-%5Cfrac%7B363%7D%7B%28t%2B11%29%5E%7B2%7D%7D%5D.%5Cfrac%7B726%7D%7B%28t%2B11%29%5E%7B3%7D%7D)
Multipying and simplifying:

The rate at which the area is increasing is given by expression
.
B. At t = 5, rate is:




At 5 seconds, the area is expanded at a rate of 1.76 cm/s.