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Taya2010 [7]
4 years ago
6

Write an equation of a line in point-slope form that is perpendicular to the line y=1/2x-7 and goes through the point (4,-3)

Mathematics
1 answer:
photoshop1234 [79]4 years ago
5 0

Answer:

y = - 2x + 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = \frac{1}{2} x - 7 ← is in slope- intercept form

with slope m = \frac{1}{2}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{1}{2} } = - 2, hence

y = - 2x + c ← is the partial equation of the perpendicular line

To find c substitute (4, - 3) into the partial equation

- 3 = - 8 + c ⇒ c = - 3 + 8 = 5

y = - 2x + 5 ← equation of perpendicular line

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What is the smallest of 3 consecutive positive integers if the product of the smaller two integers is 5 less than 5 times the la
Irina18 [472]
So consecutive intergers are 1 away from each other so
the numbers are
x,x+1,x+2
if the product (multily) of 2 smaeller is 5 less than 5 times largest so
(x times (x+1)) is 5 less than 5 times (x+2)
(x times (x+1))=-5+5(x+2)
pemdas
distribute using distributiver property
a(b+c)=ab+ac so
x times (x+1)=x^2+x
5(x+2)=5x+10
we have
x^2+x=-5+5x+10
add like terms
x^2+x=5x+5
subtract (5x+5) from both sides
x^2-4x-5=0
factor by find what 2 numbers add to -4 and multply to get -5
numbers are 1 and -5
so we do
(x+1)(x-5)=0
sete each to zero
x+1=0
x-5=0

x+1=0
sbtract 1
x=-1
we want positie so thisis wrong answer

x-5=0
add 5
x=5
subsitute
x,x+1,x+2
5,5+1,5+2
5,6,7


smalles is 5



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