Question

Please help! Thank you!

Answer 1

Answer:

699 N.

Step-by-step explanation:

Given that the dimensions are given to the nearest 0.1 metres the the lowest possible values of the dimensions are 1.55 and 2.25 which gives an area of

3.4875 m^2.

200 N to the nearest 5N could be as high as 200.49 N.

Therefore the maximum force that can be applied to the tile is therefore 200.49* 3.4875

= 699 N.

Answer 2

Answer:

736 N

Step-by-step explanation:

Area of the rectangular tile=length*breadth

=1.6*2.3 sq. metres

=3.68 sq . metres

Given, Maximum pressure sustainable by the tile=200N/sq.metres

Thus, the maximum force that can safely be applied to the tile=Pressure*Area

=200*3.68 N

=736 N