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2 years ago

12

What is the reason for each strip on the solution of the equation?

1 answer:

Pani-rosa [81]2 years ago

7 0

Step 1: Given

Step 2: Distributive Property

Step 3: Addition Property of Equality

Step 4: Division Property of Equality

Step-by-step explanation:

We need to match the reason with the correct step in the equation.

Equation:

Given:

$2x = -4(x-3)$

Applying Distributive property a(b+c)=ab+ac

$2x=-4x+12$

Now, Applying addition property of equality:

Adding +4x on both sides

$2x+4x=-4x+12+4x\\6x=12$

Now, Applying Division property of Equality:

Divide both sides by 6:

$\frac{6x}{6}=\frac{12}{6}\\x=2$

So, Answer will be:

Step 1: Given

Step 2: Distributive Property

Step 3: Addition Property of Equality

Step 4: Division Property of Equality

Keywords: Solving Equations

Learn more about Solving Equations at:

#learnwithBrainly

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Simplify the expression –3(x + 3)2 – 3 + 3x. What is the simplified expression in standard form?

andrew11 [14]

For this case we must simplify the following expression:

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We solve the parenthesis:

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We apply distributive property to the terms within parentheses:

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We add similar terms:

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Answer:

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3 years ago

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Step-by-step explanation:

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2 years ago

Find the mean, median, mode for the data set below.<br> 32, 20, 45, 20, 14, 7, 20

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2 years ago

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If log2 5 = k, determine an expression for log32 5 in terms of k.

lukranit [14]

Answer:

$log_3_2(5)=\frac{1}{5} k$

Step-by-step explanation:

Let's start by using change of base property:

$log_b(x)=\frac{log_a(x)}{log_a(b)}$

So, for $log_2(5)$

$log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)$

Now, using change of base for $log_3_2(5)$

$log_3_2(5)=\frac{log(5)}{log(32)}$

You can express $32$ as:

$2^5$

Using reduction of power property:

$log_z(x^y)=ylog_z(x)$

$log(32)=log(2^5)=5log(2)$

Therefore:

$log_3_2(5)=\frac{log(5)}{5*log(2)}=\frac{1}{5} \frac{log(5)}{log(2)}\hspace{10}(2)$

As you can see the only difference between (1) and (2) is the coefficient $\frac{1}{5}$ :

So:

$\frac{log(5)}{log(2)} =k\\$

$log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k$

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3 years ago

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3 years ago