Answer:
The angle formed between CF and the plane ABCD is approximately 47.14°
Step-by-step explanation:
The given parameters are;
BC = 6.8
DE = 9.3
∠BAC = 52°
We note that the angles formed by the vertex of a cuboid are right triangles, therefore, by trigonometric ratios, we get;
sin∠BAC = BC/(The length of a line drawn from A to C)
∴ The length of the line drawn from A to C = BC/sin∠BAC
The length of the line drawn from A to C = 6.8/sin(52°) ≈ 8.63
∴ AC = 8.63
By trigonometry, we have;
The angle formed between CF and the plane ABCD = Angle ∠ACF


In a cuboid, FA = BG = CH = DE = 9.3


The angle formed between CF and the plane ABCD = Angle ∠ACF ≈ 47.14°
-1/2(x + 2) + 1 + 1/2 x = 3
-1/2 x - 1 + 1 + 1/2 x = 3
0 = 3
x has no solution.
A = 60 but b is unsolvable, plz update question it is wrong
False, for example, if the scale factor is 2, the scale drawing would still be smaller because it would be twice as smaller than the actual object.
Answer:
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Step-by-step explanation:
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