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3 years ago

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#20 A shirt costs $15 more than a pair of shorts. Terrell paid $101 for 3 shirts and 5 pairs of shorts. How much did each shirts

cost?

1 answer:

bixtya [17]3 years ago

3 0

Answer:

$22.

Step-by-step explanation:

Let x represent cost of each shirt and y represent cost of each shorts.

We have been given that a shirt costs $15 more than a pair of shorts. We can represent this information in an equation as:

$y=x-15...(1)$

We are also told that Terrell paid $101 for 3 shirts and 5 pairs of shorts. We can represent this information in an equation as:

$3x+5y=101...(2)$

Upon substituting equation (1) in equation (2), we will get:

$3x+5(x-15)=101$

$3x+5x-75=101$

$8x-75=101$

$8x-75+75=101+75$

$8x=176$

$\frac{8x}{8}=\frac{176}{8}$

$x=22$

Therefore, the cost of each shirt is $22.

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April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

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3 years ago

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meriva

Answer:

A. A = B

Step-by-step explanation:

Given

$A = 8!$

$B = ^8P_8$

Required

Which of the options is true

We start by simplifying $B = ^8P_8$

Permutation is calculated as follows

$^nP_r = \frac{n!}{(n - r)!}$

So.

$^8P_8 =\frac{8!}{(8 - 8)!}$

$^8P_8 =\frac{8!}{0!}$

0! = 1; So

$^8P_8 =\frac{8!}{1}$

$^8P_8 =8!$

Hence. B! = P!

<em>This implies that </em> $A = B = 8!$ <em />

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

A quadratic function is a function in which the highest power of the unknown variable is 2.

Formally, a quadratic function is defined as a function of the form:

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nata0808 [166]

Answer:

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Step-by-step explanation:

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