Answer:
year 7
Step-by-step explanation:
If we assume that investment A earns interest compounded annually, its value can be modeled by the equation ...
A = 50·(1+0.08)^(t-1) . . . . . where t is the year number
The second investment earns $3 per year, so its value can be modeled by the equation ...
B = 60 + 3(t -1) . . . . . . . . . where t is the year number
We are interested in finding the minimum value of t such that ...
A > B
50·1.08^(t-1) > 60 +3(t-1)
This is a mix of exponential and polynomial terms for which no solution method is available using the tools of Algebra. A graphing calculator shows the solution to be ...
t > 6.552
The value at the end of year 1 is found for t=1, so the values of interest are seen after 6.55 years, in year 7.
5x^3 - 5x - 8 + 2x^3 + 4x + 2
7x^3 - x - 6 (some like terms)
Answer:
x 1 = -3
x2 = -3
y1 = 0
y2 = 5
The slope of that equation is infinite and the equation is a perfectly vertical line at x = -3.
So, the equation is x = -3.
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
An angle of the measure should have the same measure as an angle measured because this is periodic. If we do that, we get the angle:
Thus, the answer is A.
It's consistent and coincident because there the same equations just switch around so it's a dependent system which makes it a coincident and since the equations are consistent with each other too. :) Hope this helped!!