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Irina-Kira [14]
3 years ago
9

What would the answer for this question be

Mathematics
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

B. 20/21

Step-by-step explanation:

Tan of an angle is the ratio of the opposite side relative to the angle over the adjacent side.

The opposite side of x is 20 and the adjacent side is 21, so it's 20/21

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Please help me with this.
blondinia [14]

Answer:

D

Step-by-step explanation:

a,c,d are same but b is different.

5 0
3 years ago
A nature museum has 2008 specimens of early birds, some with 222 wings and some with 444 wings. The specimens have a total of 40
ludmilkaskok [199]

Let's assume

number of birds with 2 wings is x

number of birds with 4 wings is y

A nature museum has 2008 specimens of early birds

so,

x+y=2008

Total of wings of 2 wings bird =2x

Total of wings of 4 wings bird =4y

The specimens have a total of 4384 wings

so, we get

2x+4y=4384

we can divide both sides by 2

x+2y=2192

so, we get system of equations as

x+y=2008

x+2y=2192

we can solve for x and y

We can subtract both equations

2008-y+2y=2192

y=184

x=2008-184

x=1824

y=184,\:x=1824

so,

number of birds with 2 wings is 1824

number of birds with 4 wings is 184.............Answer



5 0
3 years ago
Sandy wants to put up a border in her room. One section of border is 7 1/3 feet long and she needs 3 1/2 sections of border. Wri
skad [1K]

Answer:

56

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A football team loses 3 yards on one play and 6 yards on another play. Write a sum of negative integers to represent this situat
stepan [7]
-3 + (-6) = -9
This relates to to the problem because the team has lost a total of nine yards.
4 0
3 years ago
What is the equation of the line that passes through the points (-3,5) (6,8)
Ratling [72]

(\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{8}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-3)}}}\implies \cfrac{3}{6+3}\implies \cfrac{3}{9}\implies \cfrac{1}{3}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-5=\cfrac{1}{3}(x+3)\implies y-5=\cfrac{1}{3}x+1\implies y=\cfrac{1}{3}x+6

6 0
2 years ago
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