The length of a freeway is 600 miles. If 0.5 inch represents 50 miles, what is the length of the freeway on the map?

Mathematics

2 answers:

kirill115 [55]3 years ago

8 0

Answer:

look it up.

Step-by-step explanation:

trasher [3.6K]3 years ago

6 0

600/50 = 12
12/2= 6 inches

You might be interested in

Fission tracks are trails found in uranium-bearing minerals, left by fragments released during fission events. An article report

Harlamova29_29 [7]

Answer:

Mean track length for this rock specimen is between 10.463 and 13.537

Step-by-step explanation:

99% confidence interval for the mean track length for rock specimen can be calculated using the formula:

M± $\frac{t*s}{\sqrt{N}}$ where

M is the average track length (12 μm) in the report
t is the two tailed t-score in 99% confidence interval (2.977)
s is the standard deviation of track lengths in the report (2 μm)
N is the total number of tracks (15)

putting these numbers in the formula, we get confidence interval in 99% confidence as:

12± $\frac{2.977*2}{\sqrt{15}}$ =12±1.537

Therefore, mean track length for this rock specimen is between 10.463 and 13.537

4 0

3 years ago

Use the graph of the function to find the domain of f. (Enter your answer using interval notation.).

Ulleksa [173]

Answer:

Domain: (-∞,0) ∪ [0,∞)

Range: [-3,∞)

f(0) = -3

6 0

3 years ago

Need help with a system of equations

sweet [91]

Answer:

$\boxed{x - y = -2\sqrt{7}}$

Given:

$x + y = 4 \\ \\ {x}^{2} + {y}^{2} = 22 \\ \\ {x}^{4} = {y}^{4} - 176 \sqrt{7}$

Step-by-step explanation:

$= > {x}^{4} = {y}^{4} - 176 \sqrt{7} \\ \\ = > {x}^{4} - {y}^{4} = - 176 \sqrt{7} \\ \\ = > {( {x}^{2}) }^{2} - { ({y}^{2}) }^{2} = - 176 \sqrt{7} \\ \\ = > ( {x}^{2} + {y}^{2} )( {x}^{2} - {y}^{2} ) = - 176 \sqrt{7} \\ \\ = > ( {x}^{2} + {y}^{2}) (x + y)(x - y) = - 176 \sqrt{?} \\ \\ = > 22 \times 4(x - y) = - 176 \sqrt{7} \\ \\ = > 88(x - y) = - 176 \sqrt{7} \\ \\ = > x - y = - \frac{176 \sqrt{7} }{88} \\ \\ = > x - y = - 2 \sqrt{7}$